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WARRIOR [948]
3 years ago
10

Find the distance between the given points.

Mathematics
2 answers:
Anna11 [10]3 years ago
8 0

Answer:

The distance would be 4 units and you would go 4 to the right

I hope this helps :)

Step-by-step explanation:

BaLLatris [955]3 years ago
3 0

Answer: First option

Step-by-step explanation:

The distance between two points is calculated using the following formula

d=\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}

In this case we have the following points

W(0, 8) and X(0, 12)

Therefore

x_1 = 0\\x_2 = 0\\y_1=8\\y_2=12

d=\sqrt{(0-0)^2 +(12-8)^2}

d=\sqrt{(12-8)^2}

d=\sqrt{(4)^2}

d=4

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fenix001 [56]

Answer:

\displaystyle y = \frac{1}{6}x + 1\frac{1}{3}

Step-by-step explanation:

First, find the <em>rate of change</em> [<em>slope</em>]:

\displaystyle \frac{-y_1 + y_2}{-x_1 + x_2} = m \\ \\ \frac{-1 + 2}{2 + 4} = \frac{1}{6}

Now plug these coordinates into the Slope-Intercept Formula. It does not matter which ordered pair you choose:

2 = ⅙[4] + b

⅔

\displaystyle 1\frac{1}{3} = b \\ \\ y = \frac{1}{6}x + 1\frac{1}{3}

_______________________________________________

1 = ⅙[−2] + b

−⅓

\displaystyle 1\frac{1}{3} = b \\ \\ y = \frac{1}{6}x + 1\frac{1}{3}

** You see? I told you it did not matter which ordered pair you choose because you will ALWAYS get the exact same result.

I am joyous to assist you anytime.

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Virty [35]
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the answer to 2d(3) is 6d.
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There are $5$ girls and $5$ boys in a chess club. The club holds a round-robin tournament in which every player plays against ev
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f(x) = tan2(x) + (√3 - 1)[tan(x)] - √3 = 0

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Then

tan(x) = 1

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