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Tanzania [10]
3 years ago
8

What is the value of x in the rhombus below?

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
8 0
It is 21 g What are the benefits and what are the drawback to certifying/licensing computer/IT professionals?
guajiro [1.7K]3 years ago
3 0

Answer:

can we have a diagram please? If not I would say 21 because it looks like 21 but would be more clear w/ diagram. Step-by-step explanation:

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What is the reciprocal Consider the expression (5) of the base? Write your answer as a fraction, using the / symbol, like this:
lora16 [44]
Reciprocal of a fraction<h2>Answer</h2>

8/7

<h2>Explanation</h2>

In this case, the base is 7/8 and the exponent is -4.

In order to find the reciprocal of a fraction we just have to flip it upside down:

That is why the answer is 8/7.

3 0
1 year ago
N is an integer and - 2&lt;n+3&lt;4, write down the possible values of n from smallest to largest​
Korolek [52]

Answer:

- 4, - 3, - 2, - 1, 0

Step-by-step explanation:

Given

- 2 < n + 3 < 4 ( subtract 3 from each interval )

- 5 < n < 1

This indicates that n ≠ - 5, 1 but all values in between, that is

n = - 4, - 3, - 2, - 1, 0 ← possible values of n

4 0
3 years ago
Help me plzzzzzzzzzzzz
Paraphin [41]

Answer: -27/7

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Please solve this sheet.
lyudmila [28]
Hello,

A: roots: -1,-3
a point (-2,1)
Vertex=((-2,1)

y=k*(x+1)(x+3) using roots
but k*(-2+1)(-2+3)=1==>k*(-1)*1=1==>k=-1

eq: y=-(x+1)(x+3)
==>y=-(x²+3x+x+3)
==>y=-x²-4x-3
y=k(x+2)²+1 if x=-1,y=0 ==>k*1+1=0==>k=-1
==>y=-(x+2)²+1

Answer :A--> R,K

B)
y=k(x+4)²-2 and k=-1/2
y=-1/2(x+4)²-2
y=-1/2x²-4x-10

answer B--> I,≈W if it is written -1/2*x²  (square has been forgotten)

C:
y=2x²-16x+30
y=2(x-4)²-2
answer : C-->S,J

D:
y=-(x+3)(x+1)
y=-x²-4x-3
=-(x+2)²+1
answer D--> V,L

E:
Here there is a problem: or the graph is wrong, or 2 equations are missing!

y=1(x+1)(x-3) using roots
y=x²-2x-3 ≈ T si it were -2x and not +2x.

y=(x-1)²-4 ≈H is it were -1 in place of +1 [H:y=(x+1)²-4]




6 0
3 years ago
sand falls from an overhead bin and accumulates in a conical pile with a radius that is always four times its height. suppose th
blagie [28]

Answer:

\frac{dv}{dt} =7239.168 cm/sec

Step-by-step explanation:

From the question we are told that:

Rate \frac{dh}{dt}=1cm

Height h=12cm

Radius r=4h

Generally the equation for Volume of Cone is mathematically given by

V=\frac{1}{3}\pi r^2h

V=\frac{1}{3}\pi (4h)^2h

Differentiating

\frac{dv}{dt} =\frac{16}{3}\pi3h^2\frac{dh}{dt}

\frac{dv}{dt} =\frac{16}{3}*3.142*3*12^2*1

\frac{dv}{dt} =7239.168 cm/sec

7 0
3 years ago
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