Which shows the distributive property?
1 answer:
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Answer:
Step-by-step explanation:
The best way to do this is to use your LCM and eliminate the fractions. To find the LCM you have to use all the denominators as a multiplier so the denominator in each term cancels out. We will first factor the x-squared term to simplify and see what 2 factors are hidden there.
factors to (x + 2)(x - 2). That means that our 3 denominators that make up our LCM are x(x+2)(x-2). We will mulitply that in to each term in our rational equation, canceling out the denominators where applicable.
In the first term, the (x-2) will cancel leaving us with
x(x+2)[2] which simplifies to
In the second term, the (x+2)(x-2) cancels out leaving us with
x[7].
In the last term, the x cancels out leaving us with
(x+2)(x-2)[5] which simplifies to
Now we will distribute through each cancellation:
2x²+4x;
7x;
5x²-20
Putting them all together we have
2x² + 4x + 7x = 5x² - 20
Combining like terms gives us a quadratic:
3x² - 11x - 20 = 0
Factor that however you find it easiest to factor quadratics and get that
x = 5 and x = -4/3
4096|2
2048|2
1024|2
512|2
256|2
128|2
64|2
32|2
16|2
8|2
4|2
2|2
1
![4096=2^{12}\\\\ \sqrt[3]{4096}=\sqrt[3]{2^{12}}=\sqrt[3]{(2^4)^3}=2^4=16](https://tex.z-dn.net/?f=4096%3D2%5E%7B12%7D%5C%5C%5C%5C%0A%5Csqrt%5B3%5D%7B4096%7D%3D%5Csqrt%5B3%5D%7B2%5E%7B12%7D%7D%3D%5Csqrt%5B3%5D%7B%282%5E4%29%5E3%7D%3D2%5E4%3D16)
2048|2
1024|2
512|2
256|2
128|2
64|2
32|2
16|2
8|2
4|2
2|2
1