Answer:
$24.11
Step-by-step explanation:
Let the cost of the present be c.
Then (3/4)c = $18.33.
To isolate (solve for) c, mult. both sides of this equation by (4/3):
(4/3)(3/4)c = (4/3)($18.33), or
c = $24.11
Angles 1 and 3 are supplementary
2a^2b^3(4a^2+3ab^2-ab)=?
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
</span>
9514 1404 393
Answer:
C. 2y = (2x-1)/4
Step-by-step explanation:
An equation is linear when the exponents of the variables are 1 and the sum of the exponents of the variables in any term is 1.
a) 3xy = 4 . . . . sum of exponents is 1+1=2
b) f(x) = 2/3(1 -x^2) . . . . exponent is 2
c) 2y = (2x -1)/4 . . . . all exponents are 1 (linear)
d) y = 3/(x+1) ⇒ xy +y = 3 . . . . sum of exponents is 1+1 = 2