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MAXImum [283]
3 years ago
12

How many pounds are in 3/4 of a ton?

Mathematics
2 answers:
alexandr402 [8]3 years ago
7 0
The answer is 1,500 pounds are in 3/4 of a ton.
Hope this helps.
morpeh [17]3 years ago
3 0

1500 lbs is 3/4 of a ton


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Two data sets are represented by the graphs below.
Bingel [31]
It’s larger median one ages the graphs looks bigger
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3 years ago
4 (2(-2) + 3(3) -2(4.2)
12345 [234]

Answer:

-15.4

Step-by-step explanation:

4(2(-2)) + 3(3) - 2(4.2)

Multiply the numbers in the parentheses first because of PEMDAS.

4(-4) + 9 - 8.4

-16 + 9 - 8.4

Now add the numbers together.

-15.4

7 0
3 years ago
What the answer to the problem 1.24÷0.4712
Firlakuza [10]
It is 2.63157894737 if you didn't know if you need any help with anything use a calculator for anything like this if you can't find your mother or father. Also look up how to divide decimals on youtube and subscribe to mathantics and numberphile to become better at math. I hope this helps.
3 0
3 years ago
What does the 99% confidence level in the previous problem tell us? Group of answer choices There is a 99% chance that this part
ArbitrLikvidat [17]

Answer:

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The margin of error is given by:

ME= z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

For this case since the confidence is 99% we are confident that the true proportion of interest would be on the interval calculated and the best option for this case is:

Of confidence intervals with this margin of error, 99% will contain the population proportion

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The margin of error is given by:

ME= z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

For this case since the confidence is 99% we are confident that the true proportion of interest would be on the interval calculated and the best option for this case is:

Of confidence intervals with this margin of error, 99% will contain the population proportion

5 0
3 years ago
Four out of every five visitors at an amusement park buy day passes what percent of the visitors buy passes?
dimaraw [331]
80% 
THis is because you are supposed to multiply 20 to the denomintaor and numerator.
4 times 20=80
~JZ
Hope it helps
7 0
3 years ago
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