<span>You are given a rectangular picture measuring 8 inches by 7 inches. Also, Alistair wants this to be framed and that the total area is 34 square inches. The width of the frame is x inches. To solve the dimension of the frame with value of x we have:
We have to assume that x here will be equal to all sides of the frame and so, using the area of the rectangle, we can model the equation like this:
A = LW (where A is the area, L is the length and W is the width)
36 = (8 - x)(7 - x)
36 = 56 - 8x - 7x + x</span>²
<span>x</span>² - 15x +20 = 0 → model of our equation and in quadratic form
x² - 15x + 20 = 0
using a calculator, x = 1.48 inches
<span>
3.Use the equation you created in part A to find the width of the picture frame</span>
The formula for the area of a circle is A = (pi)r^2
So if you plugged in the numbers you would get this equation A = (3.14)97^2
Solve the equation and you would get your answer which is 29544.26
Hope this helps! :)
Step-by-step explanation:
Since we have given that
By using logarithmic on both sides we get,
(∵ 
)
Now, differentiating on both sides ,we get,
A rectangular school banner
has a length of 44 inches, a perimeter of 156 inches, and an area of 1,496
square inches. the cheerleaders make signs similar to the banner. the length of
a sign is 11 inches. First solve the width of the rectangle:
1496 sq in/ 44 = 34 in
So the sign has also a width
of 34 in and a length of 11 so the area is 34*11 =374 sq in
<span>The perimeter is (34*2)
+(11*2) =90 in</span>
