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charle [14.2K]
3 years ago
10

Deborah has two paintings in her portfolio and paints three more each week.Kai has twelve paintings in her portfolio and paints

two more each week.After how many weeks will Deborah and Kai have the same number of paintings ?
Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
4 0
Well, we can set up these equations like this-
Deborah- 2+3w
Kai- 12+2w
w=number of weeks that pass
Now, we set them equal to each other:
2+3w=12+2w

Solve for w
2-12=2w-3w
-10 = -1w
w = 10
10 weeks. Hope this helped!
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An airplane traveled 700 kilometers in two hours during a trip. What was the average speed of the plane during the trip?
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Please help me now ! Thank you
jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

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3 years ago
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