A coin is flipped twice. What is the probability that it will come up once heads and once tails

Mathematics

1 answer:

Illusion [34]2 years ago

5 0

1/2 or 50%, because there are two possibilities out of four.

If you think about flipping a coin twice, there are exactly four possible outcomes:

Flip 1 Flip 2

1. tails heads

2. tails tails

3. heads tails

4. heads heads

In two of these possibilities (1 and 3) the coin flipped different sides.

That means 2/4 possibilities matched, and this can be reduced to 1/2

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1. A given binomial distribution has a mean of 153.1 and a standard deviation of 18.2. Would a value of 187 be considered usual

Triss [41]

Answer:

Usual, because the result is between the minimum and maximum usual values.

Step-by-step explanation:

To identify if the value is usual or unusual we're going to use the Range rule of thumbs which states that most values should lie within 2 standard deviations of the mean. If the value lies outside those limits, we can tell that it's an unusual value.

Therefore:

Maximum usual value: μ + 2σ

Minimum usual value: μ - 2σ

In this case:

μ = 153.1

σ = 18.2

Therefore:

Maximum usual value: 189.5

Minimum usual value: 116.7

Therefore, the value of 187 lies within the limits. Therefore, the correct option is D. Usual, because the result is between the minimum and maximum usual values.

8 0

2 years ago

How are y-intercepts of y=(1/3)^x and y=5(1/3)^x different?

loris [4]

Remark.
The easiest way to do this question is to graph it. Start with that.
The red line is y = (1/3)^x
The blue line is y = 5*(1/3)^x

Comment
The red line's y intercept is (0,1)
The blue line's y intercept is (0,5)

Why
If the x value is 0 then (1/3)^0 = 1
y = (1/3)^0 = 1 * 1 = 1 and for the blue graph
y = 5*(1/3)^0 = 5*1 = 5

In other words, in this set of equations, the 5 makes the y intercept 5 times larger than the 1 in front of y = (1/3)^x

If you have choices, could you please list them? I may be giving you the right answer but not in the form required.