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Salsk061 [2.6K]
3 years ago
11

For each scenario below, choose the graph that gives the best representation (must view picture for questions A and B).

Mathematics
2 answers:
Sedbober [7]3 years ago
5 0

Answer:

Part a:   Graph (2)

Part b:   Graph (2)

Step-by-step explanation:

Part A)

Lotoya is hiking toward her campsite at a constant pace.

When the time runs, the distance to reach her campsite decrease. So the distance decrease.

A few kilometers from the campsite, she sees a snake and truns and runs the other way.

So the direction changes and minutes later, she sits to rest. So the time runs but distance remains the same.

Therefore, the Graph graph (2) Represents the situation.

Part B)

Karen begins her jogging workout by running faster and faster for about a minute.

So, in 1 minutes the speed rises.

Once she hits a comfortable pace, she runs at that pace for several minutes. So the speed is constant.

Then she gradually slows down to a stop.

So the graph falls down slowly.

The above situation is represented by graph (2).

mr Goodwill [35]3 years ago
4 0
Part A would be the second option, as well as part B
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If the product of two positive fractions a and b is 15/56, find three pairs of possible values for a and b
Andrews [41]

Answer:

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

Step-by-step explanation:

According to the question,

a x b = 15/56

three possible pairs will be as follows:

Before proceeding to make possible pairs, we have to know the prime factorization of the numbers -

15 = 1, 3, 5, 15

56 = 1, 2, 4, 7, 8, 14, 28, 56

As we need three possible pairs, we have to check which pairs take us to 15/56. Again, since the fraction is positive, therefore, the fractions will be proper. Therefore, 3/2, or 5/4 will not be counted. Therefore,

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

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So, we can get those four possible pairs. Among those, first 3 pairs are different. Therefore, those are possible pairs.

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