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IrinaVladis [17]
3 years ago
13

State the possible number of positive real zeros, negative real zeros, and imaginary zeros

Mathematics
1 answer:
Snezhnost [94]3 years ago
6 0

Examine the number of sign changes for f(x) and f(-x)

f\left(x\right)=-x^3-x^2+14x-24

(-)       (-)      (+)    (-)

There are two sign changes for the coefficient of f(x), so the function has 2 or 0 positive real zeros.

f(-x)= x^3-x^2-14x-24

There is 1 sign change for the coefficients of f(-x). So f(x) has one negative real zero.

Thus, f(x) has 2 or 0 positive real zeros, 1 negative real zero, 2 or 4 imaginary zeros

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Although the graph is not given in the option, so I would consider it from a different graph with the same question. The graph that represents the area of each rectangle in terms of the change in the length and width is the one with coordinate points located on the grid. The coordinate points on the form of (x,y) are represented as: 

1. (0,40)
2. (1,45)
3. (2,47) 
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Softa [21]

Kenyan = k

$3.50 per pound

Sri Lankan = s

$5.60 per pound

6lbs of blend

$28.35

s+k = 6

3.50k + 5.60s = 28.35

where:

k = lbs of kenyan

s = lbs of Sri Lankan

Solve the system

s+k = 6

3.50k + 5.60s = 28.35

solve the first equation for s:

s = 6-k

Replace in the second equation:

3.50k + 5.60 (6-k) = 28.35

3.50k + 5.60(6)+ 5.60(-k) = 28.35

3.50k + 33.6 - 5.60k = 28.35

3.50k - 5.60k = 28.35-33.6

-2.1k= -5.25

k= -5.25/-2.1

k= 2.5 lbs

Replace k on any equation and solve for s

s+k= 6

s+ 2.5 = 6

s= 6-2.5

s= 3.5 lbs

3 0
1 year ago
A ball is thrown upward and outward from a height of 77 feet. the height of the​ ball, f(x), in​ feet, can be modeled by f left
Oksi-84 [34.3K]
From the given function modeling the height of the ball:
f(x)=-0.2x^2+1.4x+7
A] The maximum height of the ball will be given by:
At max height f'(x)=0
from f(x), 
f'(x)=-0.4x+1.4
solving for x we get:
-0.4x=-1.4
x=3.5ft
thus the maximum height would be:
f(3.5)=-0.2(3.5)^2+1.4(3.5)+7
f(3.5)=9.45 ft

b]
How far from where the ball was thrown did this occur:
from (a), we see that at maximum height f'(x)=0
f'(x)=-0.4x+1.4
solving for x we get:
-0.4x=-1.4
x=3.5ft
This implies that it occurred 3.5 ft from where the ball was thrown.


 c] How far does the ball travel horizontally?
f(x)=-0.2x^2+1.4x+7
evaluationg the expression when f(x)=0 we get:
0=-0.2x^2+1.4x+7
Using quadratic equation formula:
x=-3.37386 or x=10.3739
We leave out the negative and take the positive answer. Hence the answer 10.3739 ft horizontally.
6 0
4 years ago
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