What are the coordinates of the circumcenter of a triangle with vertices A(−1, 1) , B(5, 1) , and C(−1, −1) ?

ozzi

Answer:

y = $-\frac{3}{4}$ x

Step-by-step explanation:

slope-intercept form: y = mx + b

Given: slope(m) = $-\frac{3}{4}$ , point (4, -3)

We already have the value of m, but we need to find the value of b. To do this, input the given values of the slope and the point into the equation:

-3 = $-\frac{3}{4}$ (4) + b

Solve for b:

-3 = $-\frac{3}{4}$ (4) + b

-3 = -3 + b

0 = b

The value of b is zero. We can now write the equation:

y = $-\frac{3}{4}$ x + 0

y = $-\frac{3}{4}$ x

The equation written in slope-intercept form is: y = $-\frac{3}{4}$ x

8 0

3 years ago

Alenkinab [10]

There are 3 marbles.

4 0

3 years ago

MA_775_DIABLO [31]

Answer:

m + p >= 100

m >= 40

p >= 10

Step-by-step explanation:

let m = number of mugs

let p = number of plates

4 0

3 years ago

stiks02 [169]

The answer is: GCF(9, +7^3) = 1
Explanation:
9 = 3^2

+7 = +7×7

3 = 3

GCF = 1

9 / 1 = 9

+7 / 1 = 7

3 / 1 = 3

7 0

2 years ago

Luba_88 [7]

Step-by-step explanation:

Hey there!

The points of line AB are; (-1,-4) and (2,11).

Note:

Use double point formula and simplify it to get two eqaution.
Use condition of parallel lines, perpendicular lines to know whether the lines are parallel or perpendicular or nothing.