8p-8=-9(2p+5)-9(6-3p)
p=91
I showed the work up there and checked
She invested.. .say "a" amount on the 4% and "b" amount on the 5% one
now, she lost the 4% one or "a", so... that'd be a negative amount
now, we know both investments added together add up to 9000
and we also know the "net" receipts for the yield was 351, that simply means that whatever "b" and "a" yielded, ended up as 351
so.. what's 4% of a? well (4/100) * a or 0.04a
what's 5% of b? well (5/100) * b or 0.05b
since "a" was a loss(negative), then we know the net yield is => b - a = 351
thus
![\bf \begin{cases} b+a=9000\implies \boxed{a}=9000-b\\\\ 0.05b - 0.04a = 351\\ ----------\\ 0.05b - 0.04\left(\boxed{ 9000-b }\right) = 351 \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%0Ab%2Ba%3D9000%5Cimplies%20%5Cboxed%7Ba%7D%3D9000-b%5C%5C%5C%5C%0A0.05b%20-%200.04a%20%3D%20351%5C%5C%0A----------%5C%5C%0A0.05b%20-%200.04%5Cleft%28%5Cboxed%7B%209000-b%20%7D%5Cright%29%20%3D%20351%0A%5Cend%7Bcases%7D)
solve for "b", to see how much was invested at 5%
what about a? well, a = 9000 - b
Answer:
Subtract the minimum data value from the maximum data value to find the data range. In this case, the data range is
8
−
5
=
3
.
3
The the mean score (rounded to 2 DP) in the maths test across both classes is 63.67
What is the mean of scores?
The mean of scores is the sum of the scores for all students divided by the number of students
Class A:
mean score=39
mean score=sum of scores/number of students
39=sum of scores/11
sum of scores=39*11
sum of scores=429
Class B:
mean score=76
mean score=sum of scores/number of students
76=sum of scores/22
sum of scores=76*22
sum of scores=1672
overall mean score=(429+1672)/(11+22)
overall mean score= 63.67
Find out more about mean on:brainly.com/question/20118982
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