I think this is it, but i’m not sure about the last one
about 1 million robux cuz they each wortha bout a cent idk though on black market is cheaper
The absolute value inequality can be decomposed into two simpler ones.
x < 0
x > -8
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</h3><h3>
Which two inequalities can be used?</h3>
Here we start with the inequality:
3|x + 4| - 5 < 7
First we need to isolate the absolute value part:
3|x + 4| < 7 + 5
|x + 4| < (7 + 5)/3
|x + 4| < 12/3
|x + 4| < 4
The absolute value inequality can now be decomposed into two simpler ones:
x + 4 < 4
x + 4 > - 4
Solving both of these we get:
x < 4 - 4
x > -4 - 4
x < 0
x > -8
These are the two inequalities.
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The answer is :23
B:34
C:56
None of the points could be added to the graph f(x)=-|x+3| to keep the graph a function
<h3>How to determine the point?</h3>
The equation of the function is given as:
f(x) = - |x + 3|
The points are given as:
(0, 3) and (-3, -6)
When x = 0, we have:
f(0) = - |0 + 3|
f(0) = -3 --- different y value from (0, 3)
When x = -3, we have:
f(-3) = - |-3 + 3|
f(-3) = 0 --- different y value from (-3, -6)
This means that the x values point to different y values (this does not represent a function)
Hence, none of the points could be added to the graph f(x)=-|x+3| to keep the graph a function
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