Find the distance between -2/3 and 4/3 on a number line
1 answer:
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Answer:
A. 1.8 × Kg
B i. 3.0 × seconds
ii. 9.6 × years
C. After 9.2 × (9.2 billion) years
Step-by-step explanation:
Given that the mass of the Sun = 2× Kg.
Mass of hydrogen when Sun was formed = 76% of 2× Kg
= ×2×
Kg
= 1.52 × Kg
Mass of hydrogen available for fusion = 12% of 1.52 × Kg
= × 1.52 ×
Kg
= 1.824 × Kg
A. Total mass of hydrogen available for fusion over the lifetime of the sun is 1.8 × Kg.
B. Given that the Sun fuses 6 × Kg of hydrogen each second.
i. The Sun's initial hydrogen would last;
= 3.04 × seconds
The Sun's hydrogen would last 3.0 × seconds
ii. Since there are 31536000 seconds in a year, then;
The Sun's initial hydrogen would last;
= 9.640 × years
The Sun's hydrogen would last 9.6 × years.
C. Given that our solar system is now about 4.6 × years, then;
= 2.09
So that; 2 × 4.6 × = 9.2 ×
years
Therefore, we need to worry about the Sun running out of hydrogen for fusion after 9.2 × years.