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2 years ago

Perform the indicated operation. f(n)=n-3 g(n)=n-2 find (f+g)(6)

Mathematics

1 answer:

Grace [21]2 years ago

5 0

Answer:

Step-by-step explanation:

(f + g)(n) = f(n) + g(n) = n - 3 + n - 2 = 2n - 5 , thus

(f + g)(6) = 2(6) - 5 = 12 - 5 = 7

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Answer:

It would take them 6 minutes to paint the wall and 12 to paint the other half : 18 minutes

Step-by-step explanation:

Say that the student who can paint a wall in 12 minutes is painting half of the wall it would take them 6 minutes

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2 years ago

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Given: ∆ABC, AB = BC, BM = MC<br> AC = 40, m∠BAC = 42º<br> Find: AM

Anna [14]

Answer:

The length of AM is 26.50 units.

Step-by-step explanation:

Given information: AB = BC, BM = MC , AC = 40, ∠BAC = 42º.

Since two sides of triangle are equal, therefore the triangle ABC is an isosceles triangle.

The corresponding angles of congruents sides are always equal. So angle C is 42º.

According to the angle sum property the sum of interior angles is 180º.

$\angle B=180-42-42=96$

Law of Sine

$\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}$

$\frac{\sinB}{AC}=\frac{\sin(C}{AB}$

$\frac{\sin(96)}{40}=\frac{\sin(42}{AB}$

$AB\sin(96)=40\sin(42)$

$AB=\frac{40\sin(42)}{\sin(96)}$

$AB=26.91$

Therefore the length of AB and BC is 26.91.

Since M is midpoint of BC, so

$BM=\frac{BC}{2}=\frac{26.91}{2}=13.455$

Use Law of Cosine in triangle ABM to find the value of AM.

$a^2=b^2+c^2-2bc\cos A$

$AM^2=AB^2+BM^2-2(AB)(BM)\cos (B)$

$AM^2=(26.91)^2+(13.455)^2-2(26.91)(13.455)\cos (96)$

$AM=26.50$

Therefore the length of AM is 26.50 units.

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2 years ago

Choose the correct way to read 32.507 in word form

Elden [556K]

32.507 in word form: Thirty-two and five hundred seven thousandths

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2 years ago

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Answer:

The answer is C

Step-by-step explanation:

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2 years ago

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svp [43]

Answer:

Step-by-step explanation:

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2 years ago