Answer:
The sum of all exterior angles of BEGC is equal to 360° ⇒ answer F only
Step-by-step explanation:
* Lets revise some facts about the quadrilateral
- Quadrilateral is a polygon of 4 sides
- The sum of measures of the interior angles of any quadrilateral is 360°
- The sum of measures of the exterior angles of any quadrilateral is 360°
* Lets solve the problem
- DEGC is a quadrilateral
∵ m∠BEG = (19x + 3)°
∵ m∠EGC = (m∠GCB + 4x)°
∵ The sum of the measures of its interior angles is 360°
∴ m∠BEG + m∠EGC + m∠GCB + m∠CBE = 360
∴ (19x + 3) + (m∠GCB + 4x) + m∠GCB + m∠CBE = 360 ⇒ add the like terms
∴ (19x + 4x) + (m∠GCB + m∠GCB) + m∠CBE + 3 = 360 ⇒ -3 from both sides
∴ 23x + 2m∠GCB + m∠CBE = 375
∵ The sum of measures of the exterior angles of any quadrilateral is 360°
∴ The statement in answer F is only true
Answer:
108
Step-by-step explanation:
add all of the numbers together and thats what you get :)
Find the GCF (Greatest Common Factor)
GCF = 3
Factor out the GCF ( Write the GCF first. Then, in parentheses, divide each term by the GCF)
3(3x^2/3 + -12x/3 - 15/3)
Simplify each term in parentheses
3(x^2 - 4x - 5)
Factor x^2 - 4x - 5
<u>3(x - 5)(x + 1)</u>
Answer:
844368.7 m
Step-by-step explanation:
We are given that a typical sugar cube has an edge length of 1.00 cm.
We have to find the edge length of the box in meters.
Edge length of sugar cube=1 cm =
(
)
Volume of a sugar cube=
1 mole of sugar=
Volume of 1 unit=
Volume of
units=
Volume of box=1 mole of sugar=
Edge length of box=![\sqrt[3]{6.02\times 10^{17}}=844368.7 m](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B6.02%5Ctimes%2010%5E%7B17%7D%7D%3D844368.7%20m)
Vcyl = Vcone
pi×x^2×y = 1/3×pi×(3x)^2 (h)
pi's cancel--> x^2•y = 3x^2 (h)
h = y/3