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Lesechka [4]
3 years ago
13

4 Muffins on each plate. There are 0 plates of lemon muffins.

Mathematics
2 answers:
GaryK [48]3 years ago
7 0
For this case, the first thing we must do is define a variable.
 We have then:
 x: number of muffin plates
 We now write the expression that models the problem.
 We know there are 4 muffins in each dish, therefore, we have:
 4x

 Substituting for x = 0 we have:
 4 (0) = 0

 Answer:
 
There are 0 lemon muffins
 
d: 0
Aleks [24]3 years ago
3 0
If there are no plates of lemon muffins then there are also no lemon muffins themselves at all. Anything multiplied by 0 will always give the result of 0.

4 * 0 = 0

Answer D.
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Which equation represents a circle with a center at (-4, 9) and a diameter of 10 units?
blsea [12.9K]

Answer:

(x+4)^2 + (y-9)^2 = 25

Step-by-step explanation:

We can use the equation (x-h)^2 + (y-k)^2 = r^2

where (h,k) is the center and r is the radius

The center is at (-4,9) and the diameter is 10 which means the radius is 10/2 or 5

(x- -4)^2 + (y-9)^2 = 5^2

(x+4)^2 + (y-9)^2 = 25

3 0
3 years ago
Simplify: (sin θ − cos θ)^2 − (sin θ + cos θ)^2 A) −4sin(θ)cos(θ) B) 2 C) sin^2 θ D) cos^2 θ
N76 [4]

Answer:

-4sinθcosθ

Step-by-step explanation:

Note:

1. (a + b)^2 = a^2 + 2ab + b^2

2. (a - b)^2 = a^2 - 2ab + b^2

3. sin^2θ + cos^2θ = 1

(sinθ -cosθ)^2 - (sinθ + cosθ)^2

= sin^2θ - 2sinθcosθ + cos^2θ - (sin^2θ + 2sinθcosθ + cos^2θ)

= sin^2θ + cos^2θ - 2sinθcosθ - (sin^2θ + cos^2θ + 2sinθcosθ)

= 1 - 2sinθcosθ - (1 + 2sinθcosθ)

= 1- 2sinθcosθ -1 - 2sinθcosθ

= - 2sinθcosθ - 2sinθcosθ

= -4sinθcosθ

3 0
3 years ago
*25 points!*
mariarad [96]
Pick 2 pairs of equations t<span>hen use addition and subtraction to eliminate </span>the same variable<span> from both pairs of equations then it is left with 2 variables 
</span>Pick two pairs
<span><span>4x - 3y + z = - 10</span><span>2x + y + 3z = 0
</span></span>eliminate the same variable from each system
<span><span>4x - 3y + z = - 10</span> 
<span>2x + y + 3z = 0</span> 

<span>4x - 3y + z = - 10</span> 
<span>-4x - 2y - 6z = 0</span> 

<span>-5y - 5z = - 10</span> 

<span>2x + y + 3z = 0</span> 
<span>- x + 2y - 5z = 17</span> 

<span>2x + y + 3z = 0</span> 
<span>-2x + 4y - 10z = 34</span> 

<span>5y - 7z = 34
</span></span>Solve the system of the two new equations:
<span><span>-5y - 5z = - 10</span> 
<span>5y - 7z = 34</span> 

<span>-12z = 24</span> 
which is , <span>z = - 2</span> 

<span>-5y - 5(- 2) = - 10</span> 
<span>-5y = - 20</span> 
wich is , <span>y = 4
</span></span>substitute into one of the original equations
<span>- x + 2y - 5z = 17</span> 
<span>- x + 2(4) - 5(- 2) = 17</span> 
<span>- x + 18 = 17</span> 
<span>- x = - 1</span> 
<span>x = 1</span> 
<span>which is , </span><span>(x, y, z) = (1, 4, - 2)</span><span> 
</span>Does 2(1) + 4 + 3(- 2) = 0<span> ? Yes</span><span>

</span>
7 0
3 years ago
Can you please tell me where I did a mistake.
oksano4ka [1.4K]
Last one should be less than 3/4
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For #32 I wrote it down multiple times to make sure I get it right. I ended coming up with 46<-8x8<-6x. I tried figuring out the answer to that but I didn’t understand so I went on Socratic & it said there was no solution. Yeah
Sorry I couldn’t help with the other 2. I tried my best here.
4 0
3 years ago
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