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Ilya [14]
3 years ago
15

PLEASE HELP!! MATH QUESTION!! 20 points!!

Mathematics
2 answers:
Olenka [21]3 years ago
7 0

Answer:

the first one is a posituve

and the last 2 are negative

Step-by-step explanation:

Blababa [14]3 years ago
5 0
The first one is a posituve 

and the last 2 are negative



hope this help
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The roots of $3x^2 - 4x + 15 = 0$ are the same as the roots of $x^2 + bx + c = 0,$ for some constants $b$ and $c.$ Find the orde
Akimi4 [234]

we are given

quadratic equation as

3x^2-4x+15=0

now, we can find b and c from

x^2+bx+c=0

we can see that coefficient of x^2 is 1

so, we will have to make coefficient x^2 as 1

so, we divide both sides by 3

3x^2-4x+15=0

\frac{3x^2-4x+15}{3}= \frac{0}{3}

\frac{3x^2}{3}-\frac{4x}{3}+\frac{15}{3}= \frac{0}{3}

now, we can simplify it

x^2-\frac{4}{3}x+5= 0

now, we can compare it with

x^2+bx+c=0

we get

b=-\frac{4}{3}

c=5

so, we get order pair as

(b,c)=(-\frac{4}{3} , 5)..............Answer

6 0
3 years ago
Read 2 more answers
According to a report from the United States Environmental Protection Agency, burning one gallon of gasoline typically emits abo
Minchanka [31]

Answer:

B. The mean amount of CO_2 emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg

Step-by-step explanation:

A Type II error is the failure to reject a false null hypothesis.

Given the null and alternate hypothesis of a fuel company which wants to test a new type of gasoline designed to have lower CO_2 emissions.:

H_0: \mu = 8.9 kg\\H_a: \mu < 8.9 kg \\\text{ (where \mu is the mean amount of CO_2 emitted by burning one gallon of this new gasoline)}

where \mu is the mean amount of CO_2 emitted by burning one gallon of this new gasoline.

If the null hypothesis is false, then:

H_a: \mu < 8.9 kg

A rejection of the alternate hypothesis above will be a Type II error.

Therefore:

The Type II error is: (B) The mean amount of CO_2  emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg.

8 0
3 years ago
Assuming the conditions regarding the motion represented in the graph remain the same, determine the acceleration of the object
vovikov84 [41]

(a)

We can see that

this is a straight line

and this is the graph of velocity

we know that

acceleration is the derivative of velocity

so, slope of curve of velocity is acceleration

so, we will find slope of this line

We can select any two points

(0,4) and (5,7)

we can use slope formula

m=\frac{y_2-y_1}{x_2-x_1}

now, we can plug points

m=\frac{7-4}{5-0}

m=0.6

we know that slope of line is always constant irrespective of any value of t

so, acceleration will always be same irrespective of any value of t

so, we will get acceleration

a(t)=0.6m/s^2............Answer

(b)

we can see that acceleration is constant

and we know that

derivative of constant is always 0

so, instantaneous rate of acceleration at t=10s is 0........Answer

7 0
3 years ago
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Give the slope between the points<br> (-2,3) (-5, -9)
valentina_108 [34]
M = (-9 - 3) / (-5 - -2)
m = -12 / -3
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The slope is 4.
4 0
2 years ago
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You can buy 8 apples for $4 how many can you buy for $10
andrey2020 [161]

Answer: 20 apples, because if you say 8 apples=$4, then that means 2 apples =$1, so $10=20 apples


Step-by-step explanation:


6 0
3 years ago
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