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3 years ago

HELP IM GOING TO CRYY!!! Find the total area of the figure below. Round your answer to the nearest tenth.

Mathematics

1 answer:

aleksklad [387]3 years ago

6 0

Answer:

349.94

Step-by-step explanation:

First u add all the square sides because they all are the same which gives u 196 then u can see there is two half circles which if they add up will be a circle and the diameter is the same as the square sides then if the diameter is 14 then the radius will be 7 becaue 14/2 therefore u use the area of the circle which is

$\pi \times {7}^{2}$

then u add all the numbers.

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What is the quotient of 5s ad 8

butalik [34]

Answer:

0.625 s

Step-by-step explanation:

5s/8

0.625 s

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3 years ago

If you answered 37 problems correctly on a 42 question test, what percent would you recieve

OleMash [197]

The fraction would be 37 out of 42. You basically divide the two and get something around 88%.

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3 years ago

ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions

aliina [53]

Answer: B. H(t) = -6.9(t - 2.3)² + 112

<u>Step-by-step explanation:</u>

The vertex form of a quadratic equation is: y = a(x - h)² + k

where (h, k) is the vertex ⇒ k is the maximum height

the distance traveled is when y = 0 ⇒ $x=\sqrt{\dfrac{-k}{a}}+h$

Given: H(t) = -7.1(t - 2.3)² + 98

maximum height (k) = 98 feet

distance traveled (x) = $\sqrt{\dfrac{-98}{-7.1}}+2.3$ = 6.02 seconds

A) H(t) = -7.5(t - 2.2)² + 112

maximum height (k) = 112 feet

distance traveled (x) = $\sqrt{\dfrac{-112}{-7.5}}+2.2$ = 6.06 seconds

B) H(t) = -6.9(t - 2.3)² + 112

maximum height (k) = 112 feet

distance traveled (x) = $\sqrt{\dfrac{-112}{-6.9}}+2.3$ = 6.33 seconds

C) H(t) = -6.9(t - 2.4)² + 95

maximum height (k) = 95 feet

This has a lower height than the given equation.

D) H(t) = -7.5(t - 2.3)² + 95

maximum height (k) = 95 feet

This has a lower height than the given equation.

Both options A and B travel higher and stay in the air longer than last year's winner, however option B stays in the air longer than option A.

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2 years ago

Plz..... Solve this questions for me...

faust18 [17]

$6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================$

$7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================$

$8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10$

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2 years ago

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vichka [17]

Your fraction that is equal to 3/12 is 1/4

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2 years ago