All categories

2 years ago

Which statement best describes the electric field around a positive charge?

Mathematics

2 answers:

horrorfan [7]2 years ago

6 0

Answer:

C. Lines with arrows that point outward radiate from the charge in all

directions.

ipn [44]2 years ago

5 0

Answer:

C. Lines with arrows that point outward radiate from the charge in all

directions.

Step-by-step explanation:

Just Took The Test And Got a 100

MHA

You might be interested in

A certain slot machine has three identical independent wheels, each with 13 symbols as follows: 1 bar, 2 lemons, 2 bells, 2 plum

kari74 [83]

Answer:

Step-by-step explanation:

Given

there are 13 symbols in slot machines i.e. 1 bar , 2 lemons , 2 bells ,2 plums ,3 cherries , 3 oranges

there are Total of 3 machines

Probability of getting bar in machine is $\frac{1}{13}$

Probability of getting 3 bar on 3 machine $=\frac{1}{13} \times\frac{1}{13}\times \frac{1}{13}=\frac{1}{2197}=0.0004$

Probability of getting an orange $=\frac{3}{13}$

Probability of getting 3 oranges on 3 machine $=\frac{3}{13} \times\frac{3}{13}\times \frac{3}{13}=\frac{27}{2197}=0.0122$

Probability of getting a Plum $=\frac{2}{13}$

Probability of getting 3 Plums on 3 machine $=\frac{2}{13} \times\frac{2}{13}\times \frac{2}{13}=\frac{8}{2197}=0.0036$

5 0

2 years ago

Easy question Give a formula used for finding the area of a square. Then use the formula to find the area of a square with a sid

Alik [6]

A=s^2

A=6.3^2

(A=6.3x6.3)

And your answer would be:

A=39.69cm^2

4 0

3 years ago

According to the picture association of America, 4% of all moves advertising is on the internet and 1 10s of all movie advertisi

Annette [7]

1 of 10 is equivalent to 10% because 1/10 is .10 and .10•100% is 10% so the newspapers advertising is higher

7 0

2 years ago

Two different simple random samples are drawn from two different populations. The first sample consists of 30 people with 16 hav

Furkat [3]

Answer:

There is no significant evidence that p1 is different than p2 at 0.01 significance level.

99% confidence interval for p1-p2 is -0.171 ±0.237 that is (−0.408, 0.066)

Step-by-step explanation:

Let p1 be the proportion of the common attribute in population1

And p2 be the proportion of the same common attribute in population2

$H_{0}$ : p1-p2=0

$H_{a}$ : p1-p2≠0

Test statistic can be found using the equation:

$z=\frac{p2-p1}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

p1 is the sample proportion of the common attribute in population1 ( $\frac{16}{30} =0.533$ )

p2 is the sample proportion of the common attribute in population2 ( $\frac{1337}{1900} =0.704$ )

p is the pool proportion of p1 and p2 ( $\frac{16+1337}{30+1900}=0.701$ )

n1 is the sample size of the people from population1 (30)

n2 is the sample size of the people from population2 (1900)

Then $z=\frac{0.704-0.533}{\sqrt{{0.701*0.299*(\frac{1}{30} +\frac{1}{1900}) }}}$ ≈ 2.03

p-value of the test statistic is 0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.

99% confidence interval estimate for p1-p2 can be calculated using the equation

p1-p2± $z*\sqrt{\frac{p1*(1-p1)}{n1}+\frac{p2*(1-p2)}{n2}}$ where

z is the z-statistic for the 99% confidence (2.58)

Thus 99% confidence interval is

0.533-0.704± $2.58*\sqrt{\frac{0.533*0.467}{30}+\frac{0.704*0.296}{1900}}$ ≈ -0.171 ±0.237 that is (−0.408, 0.066)

7 0

2 years ago

What is M ∠KNL ? Circles

alex41 [277]

Answer:

Do you still need help with this problem?

5 0

2 years ago