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3 years ago

Which statement best describes the electric field around a positive charge?

Mathematics

2 answers:

horrorfan [7]3 years ago

6 0

Answer:

C. Lines with arrows that point outward radiate from the charge in all

directions.

ipn [44]3 years ago

5 0

Answer:

C. Lines with arrows that point outward radiate from the charge in all

directions.

Step-by-step explanation:

Just Took The Test And Got a 100

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Solve (x − 2) = 3 Give your solutions correct to 3 significant figures.

Pachacha [2.7K]

Answer:

(x − 2) = 3

Remove the bracket

x - 2 = 3

Group the constants at one side of the equation

x = 2 + 3

x = 5

Therefore x = 5.00 to 3 significant figures.

Hope this helps

6 0

4 years ago

two positive integers are 3 units apart on a number line. their product is 180. wich equation can be used to solve for m, the gr

3241004551 [841]

Answer:

m^2-3m-180=0

m=15

Step-by-step explanation:

greater integer = m

small integer = n

we know that m = n+3 or n = m-3

we also know that n*m = 180

replace n for m-3

(m-3)*m=180

m^2-3m-180 = 0

(m-15)(m+12)=0

so m = 15 or -12, but since problem states positive, m=15

5 0

3 years ago

Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)

Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

$x^{2} +y^{2}+4x-1=0$

Step-by-step explanation:

Explanation:-

Step 1:-

The equation of the circle having center and radius is

$(x-h)^2+(y-k)^2=r^2$

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

$(\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2} )$

$(-2,0)$

therefore center (h,k) = (-2,0)

Step 2:-

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

$\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}$

$r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}$

$r=\sqrt{5}$

Step 3:-

center (h,k) = (-2,0) and

radius $r=\sqrt{5}$

The standard form of circle equation

$(x-h)^2+(y-k)^2=r^2$

$(x-(-2))^2+(y-0)^2=\sqrt{5} ^2$

on simplification is

$x^{2} +y^{2}+4 x-1=0$

5 0

3 years ago

Select the correct answer.

SCORPION-xisa [38]

Answer:

d. 18

Step-by-step explanation:

g(x)=3x-3

3(7)-3

21-3

=18

7 0

3 years ago

How to change the standard form of the equation to slope-intercept form

gavmur [86]

Example 2x + y =3
-2x -2x
——————————————
Y = 3 - 2x or y = -2x - 3

7 0

3 years ago

Read 2 more answers