All categories

3 years ago

ASAP PLEASE !!!EXTRA POINTS!!! PLEASE GIVE THE RIGHT ANSWER !!

Mathematics

2 answers:

Naddika [18.5K]3 years ago

6 0

A histogram would be easier! Go with that!

densk [106]3 years ago

3 0

In my personal opinion I would have to say dot-plot

Step-by-step explanation:

You might be interested in

What is nine times for a total loss of 15 3/4 yards

love history [14]

Try feet /cm or inches

7 0

3 years ago

What isn't the bets approximation for the area of this circle labeled 8 inches use3.14 to approximate pi

Arte-miy333 [17]

Answer:

50.272 in^2

Step-by-step explanation:

Step one:

Given data

Circles are described using the diameter parameter

Diameter of the circle is 8 inches

radius = 4 inche= d/2

Step two:

The area of the circle is

A= πr^2

A= 3.142*4^2

A=3.142*16

A=50.272 in^2

8 0

3 years ago

What is the slope of the line that passes through (8,4) and (6,7)?

bija089 [108]

$slope=\frac{y_2-y_1}{x_2-x_1}\\\\ 
(x_1,y_1)=(8,4)\\ 
(x_2,y_2)=(6,7)\\\\
 slope=\frac{7-4}{6-8}=\frac{3}{-2}=-\frac{3}{2}\\\\
Slope\ is\ equal\ to\ -\frac{3}{2}.
$

4 0

3 years ago

A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student

umka2103 [35]

Answer:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_{M}= 69.8$ represent the mean for the age of grandmother

$\bar X_{F}= 71.6$ represent the mean for the age of grandfather

$s_{M}= 8.38$ represent the sample deviation for the age of grandmother

$s_{F}= 6.65$ represent the sample deviation for the age of grandfather

$n_M = n_F= 10$

Solution to the problem

For this case the confidence interval is given by:

$(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_M +n_F-2=10+10-2=18$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that $t_{\alpha/2}=2.101$