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3 years ago

An iPhone costs £750 in London, €800 in Paris and $1,050 in New York.

Mathematics

1 answer:

klemol [59]3 years ago

5 0

Answer:

The iPhone is cheapest in Paris, where it costs £701.75.

Step-by-step explanation:

Divide each price by the conversion factor.

$\text{London: } \£750\\\text{Paris: } \text{EUR }800/1.14=\£701.75\\\text{New York: } \$1050/1.39=\£755.40$

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The mosquito population is a function of rainfall, and can be approximated by the formula N(x)=−x3+45x2+1000 where x is the numb

KiRa [710]

Answer:

Therefore the population will be maximum when x=30 inches.

Step-by-step explanation:

Given that, the mosquito population is a function of rainfall and can be approximated by the formula

$N(x)= -x^3+45x^2+1000$

where x is the number of inches of rainfall.

$N(x)= -x^3+45x^2+1000$

Differentiating with respect to x

$N'(x)= -3x^2+90x$

Again differentiating with respect to x

$N''(x)=-6x+90$

Now we set N'(x)=0

$-3x^2+90x=0$

$\Rightarrow -3x(x-30)=0$

$\Rightarrow x=0,30$

$N''(0)=-6.0+90=90>0$

$N''(30)=-6.30+90=-90$

Since at x=30, N''(x)<0, So at x=30, N(x) has maximum value.

Therefore the population will be maximum when x=30 inches.

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3 years ago

Geometry 100 pts plz help!!! screenshot attatched

nirvana33 [79]

Answer:

1. A

2. D

3. C

4. E

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Step-by-step explanation:

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3 years ago

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If line segment BH = 3, line segment BF = 10, line segment GH= 2, find HD 15 11 10.5 ?

pav-90 [236]

HD = 10.5

Step-by-step explanation:

Given BH = 3, GH = 2, BF = 10

Step 1: To find HF:

HF = BF – BH

HF = 10 – 3

HF = 7

Step 2: To find HD:

We know that if two chords intersects inside a circle, the product of the lengths of the segments of one chord equals the product of the lengths of the segments of the other chord.

⇒ GH × HD = BH × HF

⇒ 2 × HD = 3 × 7

⇒ HD = 10.5

Hence, the value of HD = 10.5.

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3 years ago

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F(x)= x2 + 5x at x = 4<br><br>

Viktor [21]

Answer:

x)x+5x

Step-by-step explanation:

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3 years ago

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Answer. it fast please

mojhsa [17]

Answer:

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}$

Step-by-step explanation:

Given

$(\frac{6}{10})^3 * (\frac{5}{9})^2$

Required

Solve:

$(\frac{6}{10})^3 * (\frac{5}{9})^2$

Simplify 6/10

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{9})^2$

Express 9 as 3^2

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{3^2})^2$

Apply law of indices

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{(3^2)^2}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{3^4}$

Express as a sing;e fraction

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3*5^2}{5^3*3^4}$

Apply law of indices:

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^{3-2}*3^{4-3}}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^1*3^1}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5*3}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}$

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3 years ago