It is equivalent to 17.7165 inches.
The coefficient matrix is build with its rows representing each equation, and its columns representing each variable.
So, you may write the matrix as
![\left[\begin{array}{cc}\text{x-coefficient, 1st equation}&\text{y-coefficient, 1st equation}\\\text{x-coefficient, 2nd equation}&\text{y-coefficient, 2nd equation} \end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Ctext%7Bx-coefficient%2C%201st%20equation%7D%26%5Ctext%7By-coefficient%2C%201st%20equation%7D%5C%5C%5Ctext%7Bx-coefficient%2C%202nd%20equation%7D%26%5Ctext%7By-coefficient%2C%202nd%20equation%7D%20%5Cend%7Barray%7D%5Cright%5D%20%20)
which means
![\left[\begin{array}{cc}4&-3\\8&-3\end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4%26-3%5C%5C8%26-3%5Cend%7Barray%7D%5Cright%5D%20%20)
The determinant is computed subtracting diagonals:
![\left | \left[ \begin{array}{cc}a&b\\c&d\end{array}\right]\right | = ad-bc](https://tex.z-dn.net/?f=%20%5Cleft%20%7C%20%5Cleft%5B%20%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%5Cright%20%7C%20%3D%20ad-bc%20)
So, we have
![\left | \left[\begin{array}{cc}4&-3\\8&-3\end{array}\right] \right | = 4(-3) - 8(-3) = -4(-3) = 12](https://tex.z-dn.net/?f=%20%5Cleft%20%7C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4%26-3%5C%5C8%26-3%5Cend%7Barray%7D%5Cright%5D%20%5Cright%20%7C%20%3D%204%28-3%29%20-%208%28-3%29%20%3D%20-4%28-3%29%20%3D%2012%20%20)
Answer: the third option is the correct answer
Step-by-step explanation:
From the given right angle triangle,
The hypotenuse of the right angle triangle is 16√3
With m∠30 as the reference angle,
the adjacent side of the right angle triangle is x.
the opposite side of the right angle triangle is y.
To determine x, we would apply
the cosine trigonometric ratio.
Cos θ, = adjacent side/hypotenuse. Therefore,
Cos 30 = x/16√3
√3/2 = x/16√3
x = √3/2 × 16√3 = 3 × 8
x = 24
To determine y, we would apply
the Sine trigonometric ratio.
Sin θ, = opposite side/hypotenuse. Therefore,
Sin 30 = y/16√3
1/2 = y/16√3
y = 16√3 × 1/2
y = 8√3
Answer:
792
Step-by-step explanation:
It's a combination question. The order is of no consequence. Also the fact that there are juniors and seniors is not important either.
So the answer is
12C5
12!
====
(12 - 5)! * 5!
12 * 11 * 10 * 9 * 8
==============
5 * 4 * 3 * 2 * 1
792
Answer:
B
Step-by-step explanation:
The <u>sample space</u> for this experiment is the set of all possible outcomes.
A student rolls a number cube whose six faces are numbered 1 through 6.
Therefore, all possible outcomes are:
- rolled number 1;
- rolled number 2;
- rolled number 3;
- rolled number 4;
- rolled number 5;
- rolled number 6.
Hence, the sample space is {1, 2, 3, 4, 5, 6}
