1.41 times
1) Well, let's get started by writing out the equation:
![S=\sqrt[]{gL}](https://tex.z-dn.net/?f=S%3D%5Csqrt%5B%5D%7BgL%7D)
2) Let's find out the maximum walking speed of a giraffe, plugging into that the given data: Giraffe Leg Length: 6
![\begin{gathered} S_{\text{giraffe}}=\sqrt[]{32\times6} \\ S_{\text{giraffe}}=\sqrt[]{192}\approx13.86 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20S_%7B%5Ctext%7Bgiraffe%7D%7D%3D%5Csqrt%5B%5D%7B32%5Ctimes6%7D%20%5C%5C%20S_%7B%5Ctext%7Bgiraffe%7D%7D%3D%5Csqrt%5B%5D%7B192%7D%5Capprox13.86%20%5Cend%7Bgathered%7D)
And the hippotamus:
![S_{\text{hippo}}=\sqrt[]{32\times3}\Rightarrow\sqrt[]{96}\approx9.80](https://tex.z-dn.net/?f=S_%7B%5Ctext%7Bhippo%7D%7D%3D%5Csqrt%5B%5D%7B32%5Ctimes3%7D%5CRightarrow%5Csqrt%5B%5D%7B96%7D%5Capprox9.80)
And now how many times greater by dividing the giraffe's speed by the hippopotamus speed:

Hence, the answer is 1.41 times.
Answer:
A, B, D
Step-by-step explanation:
A) y squared times y squared you just add the exponents
B) y^6/y^2 write it out as (y)(y)(y)(y)(y)(y)/(y)(y) then u cancel out two "y" from numerator and denominator and is left with y^4
C) is just 0 so its wrong
D) is the same process as B just cancel out 5 "y" from numerator and denominator and is left with y^4
E) is incorrect bc you need to add the exponents and you will get y^5 which is not equal to y^4 so yeah its wrong
Answer:
17.0
Step-by-step explanation:
0 has no value.
Which means 17.000000000 = 17.
As a decimal, 17 is the only number with a number Value.
The decimal point and the 0 don’t change the number 17.
Answer:
74.42
Step-by-step explanation:
(150-86):86*100 =
(150:86-1)*100 =
174.41860465116-100 = 74.42
Answer:
The "zeros" of the quadratic equation occur when f(x) (or "y") equals zero. The place on the graph where y = 0 is the x-axis. So the zeros are the same as the x-intercepts. we can see that we are multiplying two linear factors together and the result is zero.
Step-by-step explanation:hope this helps