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3 years ago

What is the inverse of the function below?

Mathematics

2 answers:

vodomira [7]3 years ago

8 0

Answer: C

Step-by-step explanation: With inverse equations, you switch y and x (y=f(x)) and undo/reverse the steps towards x.

1. Multiply by 3

2. Add 2

Equation by itself

0. x

1. 3(x)

2. 3(x+2)

galben [10]3 years ago

5 0

The answer is c. f^-1(x) = 3(x + 2)

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Verify the identity. cot(x - pi/2) = -tan(x)

gizmo_the_mogwai [7]

Answer:

See below.

Step-by-step explanation:

$\cot(x-\frac{\pi}{2})=-\tan(x)$

Convert the cotangent to cosine over sine:

$\frac{\cos(x-\frac{\pi}{2} )}{\sin(x-\frac{\pi}{2})} =-\tan(x)$

Use the cofunction identities. The cofunction identities are:

$\sin(x)=\cos(\frac{\pi}{2}-x)\\\cos(x)=\sin(\frac{\pi}{2}-x)$

To convert this, factor out a negative one from the cosine and sine.

$\frac{\cos(-(\frac{\pi}{2}-x ))}{\sin(-(\frac{\pi}{2}-x))} =-\tan(x)$

Recall that since cosine is an even function, we can remove the negative. Since sine is an odd function, we can move the negative outside:

$\frac{\cos((\frac{\pi}{2}-x ))}{-\sin((\frac{\pi}{2}-x))} =-\tan(x)\\-\frac{\sin(x)}{\cos(x)} =-\tan(x)\\-\tan(x)\stackrel{\checkmark}{=}-\tan(x)$

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3 years ago

A social psychologist predicted that ratings of an individual’s social desirability would be influenced by their physical attrac

marshall27 [118]

Answer:

It is stated in the query that the more attractive the individual, the higher their rank of desirability.

Step-by-step explanation:

This means that we should conclude that the alternative explanation of "higher degree of desire contributes to higher levels of social attractiveness"

In the event of a null hypothesis, we will believe that the degree of attractiveness has no impact on the score of cultural desirability.

(1) Null hypothesis:- The level of attraction does not have an impact on the rating of social desirability.

(2) Alternate hypothesis:- The level of attraction has a positive effect on the ranking of social desirability.

(3) The error of Type I is characterized as the rejection of the true null hypothesis. Therefore, in this case, the type I mistake would be that "the level of attraction has a positive effect on the rating of social desirability while the level of attraction does not have an impact on the rating of social desirability."

(4) The error of type II is characterized as the failure to reject the false null hypothesis. Thus, in this situation, the Type II error would be that "the level of attraction has no impact on the rating of social desirability while the real level of attraction has a positive effect on the rating of social desirability."

(5) We know that the likelihood of having a Form I error is equal to the degree of significance (in percent terms). The significance level, in this case, is 0.05, so the likelihood of making a form I error is 0.05 * 100=5 percent.

Therefore, there is a 5 percent risk of making a Type I mistake.

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3 years ago

27. TEMPERATURE Eleven Fahrenheit temperatures are shown on a map during

ser-zykov [4K]

Answer:

5 negative numbers

Step-by-step explanation:

-5 -4 -3 -2 -1 0 1 2 3 4 5

1 2 3 4 5 6 7 8 9 10 11

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3 years ago

Thomas is opening a savings account. Which integer represents his possible balance after making a deposit?

Ray Of Light [21]

10 is the answer …………..

8 0

2 years ago

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Assume the sample below is a perfectly random sample of students at a school. How much greater is the mean of the

igor_vitrenko [27]

Answer:

0.75

Step-by-step explanation:

The table is not well presented (See Attachment)

There are at least two approaches to this question

Method 1:

Steps

1. Calculate the mean of reported heights

Mean of reported heights = (61+68+57.5+48.5+75+65+80+68+69+63)/10

Mean of reported heights = 655/10

Mean of reported heights = 65.5

2. Calculate the mean of measured heights

Mean of measured heights = (62 + 68 + 56.5 + 47 + 72 + 65 + 78 + 67 + 69.5 + 62.5)/10

Mean of measured heights = 647.5/10

Mean of measured heights = 64.75

3. Get their difference

Difference = Mean of reported heights - Mean of measured heights

Difference = 65.5 - 64.75

Difference = 0,75

Method 2: Calculate the mean of their difference

Mean of difference = Sum of difference / Number of observations

Mean of difference = (-1 + 0 + 1 + 1.5 + 3 + 0 + 2 + 1 – 0.5 + 0.5)/10

Mean of difference = 7.5/10

Mean of difference = 0.75

Note that in both cases, the result is 0,75.

Hence, the reported heights at the school is 0.75 greater than the actual measured height

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3 years ago

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