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3 years ago

Graph the equation (x - 3)^2 + (y - 2)^2 = 25 and y = 6.

Mathematics

1 answer:

Dmitriy789 [7]3 years ago

3 0

Answer:

x=6, x=0

Step-by-step explanation:

$(x - 3) ^{2}$ + $(y - 2) ^{2}$ = 25

$(x - 3) ^{2}$ + $(6 - 2) ^{2}$ = 25

x=6, x=0

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Ramesh marks 48,56,98 what is average

gizmo_the_mogwai [7]

Answer:

Ramesh scores about 67.3

Step-by-step explanation:

To find average we need add all the numbers and divide by the number of numbers so:

48+56+98=202

202/3= 67.333

67.33%

4 0

3 years ago

A coin collector has $45 in just dimes and quarters in a piggy bank he counted all the coins and there are 240 total how many ea

Whitepunk [10]

Answer:

The number of dimes are 100 and number of quarters are 140.

Step-by-step explanation:

Let the number of dimes be 'd' and quarters be 'q'.

Given:

The sum of amount is $45.

The total number of coins are 240.

1 dime = $0.10

∴ 'd' dimes = $\$0.10d$

1 quarter = $0.25

∴ 'q' quarters = $\$0.25q$

Now, as per question:

$d+m=240-----1\\0.1d+0.25q=45---2$

Multiplying equation (1) by -0.1 and adding the result to equation (2), we get:

$-0.1d-0.1q=240\times -0.1\\-0.1d-0.1q=-24\\0.1d+0.25q=45\\-----------\\0.15q=21\\q=\frac{21}{0.15}=140\\\\d=240-q=240-140=100$

Therefore, the number of dimes are 100 and number of quarters are 140.

7 0

3 years ago

Dimensions of a prism has a scale factor of 7/4 how will this affect surface area Plz help

Margaret [11]

The surface area will increase by a factor of 49/16

6 0

3 years ago

Find the following integral

ololo11 [35]

There's nothing preventing us from computing one integral at a time:

$\displaystyle \int_0^{2-x} xyz \,\mathrm dz = \frac12xyz^2\bigg|_{z=0}^{z=2-x} \\\\ = \frac12xy(2-x)^2$

$\displaystyle \int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy = \frac12\int_0^{1-x}xy(2-x)^2\,\mathrm dy \\\\ = \frac14xy^2(2-x)^2\bigg|_{y=0}^{y=1-x} \\\\= \frac14x(1-x)^2(2-x)^2$

$\displaystyle\int_0^1\int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy\,\mathrm dx = \frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx$

Expand the integrand completely:

$x(1-x)^2(2-x)^2 = x^5-6x^4+13x^3-12x^2+4x$

Then

$\displaystyle\frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx = \left(\frac16x^6-\frac65x^5+\frac{13}4x^4-4x^3+2x^2\right)\bigg|_{x=0}^{x=1} \\\\ = \boxed{\frac{13}{240}}$

4 0

3 years ago

Adding and subtracting the given polynomials

Usimov [2.4K]

You have to combine like terms, so the variable (x, y, s, d, c....) and the exponents must be the same in order to combine them.

For example:

x² + x³ Since they don't have the same exponent, you can't combine them

y² + 3y² = 4y²

23x + x = 24x

4. 2s² + 1 + s² - 2s + 1 You can rearrange it if it makes it easier

2s² + s² - 2s + 1 + 1 = 3s² - 2s + 2

5. 5t² - 2t - 1 - (3t² - 5t + 7) Distribute/multiply the - to (3t² - 5t + 7)

5t² - 2t - 1 - 3t² + 5t - 7 = 2t² + 3t - 8

Do the same for #9 and #10, and you should get:

9. 2k² + 5k - 9

10. 6y³ - 7y² - 6y - 12

3 0

3 years ago