1. The stratosphere is above the troposphere. This layer of the atmosphere is where planes fly. At the top of the stratosphere, there is a ozone layer.
2. The mesosphere is above the stratosphere. Temperatures drastically drop in the mesosphere. It is the middle layer of the atmosphere.
3. Here are the layers of the atmosphere:
- Troposphere
- Stratosphere
- Mesosphere
- Thermosphere
- Exosphere
Hope this helps you!
Answer:
Option A, Boyle's law
Explanation:
The complete question is
Pressure and volume changes at a constant temperature can be calculated using
a. Boyle's law. c. Kelvin's law.
b. Charles's law. d. Dalton's law.
Solution
In Boyle’s law, the gas is assumed to be ideal gas and at constant temperature. With these two conditions fixed, Boyle’s established that volume of gas varies inversely with the absolute pressure.
The basic mathematical representation of this phenomenon is as follows -
OR
Where P is the pressure of ideal gas, V is the volume and k is the constant of proportionality.
Hence, option A is correct
Answer:
0.04455 Hz
Explanation:
Parameters given:
Wavelength, λ = 6.5km = 6500m
Distance travelled by the wave, x = 8830km = 8830000m
Time taken, t = 8.47hours = 8.47 * 3600 = 30492 secs
First, we find the speed of the wave:
Speed, v = distance/time = x/t
v = 8830000/30492 = 289.58 m/s
Frequency, f, is given as velocity divided by wavelength:
f = v/λ
f = 289.58/6500
f = 0.04455 Hz
The uncertainty of the measurement is 0.001 gm.
The uncertainty in the measurement of a physical quantity is given as how precisely we can measure that, in this case as we can see that the mass of the sodium chloride is precisely given as 29.732 gm, this means the electronic scale is precise to 0.001 gm and round of the values after that which means there is a uncertainty of 0.001 gm.
To solve this problem we will consider the concepts related to the normal deformation on a surface, generated when the change in length is taken per unit of established length, that is, the division between the longitudinal fraction gained or lost, over the initial length. In general mode this normal deformation can be defined as
Here,
= Change in final length 
and the initial length 
PART A)
PART B)
PART C)
Therefore the rank of this deformation would be B>C>A
