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3 years ago

Use a transformation to solve the equation. W/4 = 8

1 answer:

7 0

Transformation in this case means opposite. W/4 = 8 is a division equations but transformed it becomes multiplication aka 8 x 4 = w. W is 32.

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PLEASE HELP ME EVERYONE HAS GOTTEN THIS WRONG ITS GONNA SUBMIT IN 15 MIN PLS HELP THANK YOU

LiRa [457]

Answer:

x=4.8

This here you use Pythagorean Theorem.

Step-by-step explanation:

a^2+b^2=c^2

The longest side is c. And the two legs are a and b.

So it'd be 11^2+x^2=12^2

121+x^2=144

Subtract 121 from both sides.

x^2=23

Then take the √ of x^2 and 23

So √x^2=√23

x=4.8

Hope this helps

5 0

3 years ago

Can someone please help me work out the missing angles please I’m struggling

Vladimir [108]

Step-by-step explanation:

a =45°

b=45°

c=30°

d=30°

e=30°

f=30°

total of the angle

90×4=360

6 0

3 years ago

Read 2 more answers

Use the shell method to find the volume of the solid generated by revolving the regions bounded by the curves and lines about th

RSB [31]

Answer:

The volume of the solid is:

$\displaystyle\frac{19\pi}{6}$

Step-by-step explanation:

See the graph of the region attached.

To find the intersection between the line and the parabola we set the equation equal to each other, and solve that quadratic equation by factorization:

$x^2=9-8x\\x^2+8x-9=0\\(x+9)(x-1)=0\\x=-9,x=1$

Since the region is the one for $x\ge 0$ then the intersection we are interested on is x=1 as it can also be seen in the graph.

Then we set the integral using shell method for revolving about the y-axis:

$\displaystyle\int_a^b 2\pi\,x\,h(x)\,dx$

Where h(x) is the height of the shell which here is the distance between the parabola and the line, so $8x-9-x^2$ (since the line is on the top we subtract from it the parabola)

Then the integral becomes:

$\displaystyle\int_0^1 2\pi\,x\,(8x-9-x^2)\,dx$

Notice the limits of the integral are the x-axis (x=0) and the intersection of the parabola and the line that we found before (x=1)

Now, solving the integral:

Start by factoring the $2\pi$ and distributing the x:

$=\displaystyle2\pi \int_0^19x-8x^2-x^3dx$

Then use the basic rule to integrate:

$=\displaystyle2\pi \left[\frac{9x^2}{2}-\frac{8x^2}{3}-\frac{x^4}{4}\right|_0^1$

Then evaluate the antiderivative in the limits and subtract:

$=\displaystyle2\pi\left[\frac{9}{2}-\frac{8}{3}-\frac{1}{4}-0\right]=\frac{19\pi}{6}$

So the volume of the solid is $\displaystyle\frac{19\pi}{6}$

4 0

3 years ago

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, t in seconds, by th

amid [387]

Answer:

Step-by-step explanation:

sda

vaas

5 0

3 years ago

Explain how to estimate 360+231 two different ways

trapecia [35]

One way to estimate is by rounding to the nearest hundreds. (400 + 200), The other way is by rounding to the nearest tens (360 + 230). I hope this helped you out and answered your question! Good luck!

4 0

3 years ago