Answer:
36.666 (The six keeps going)
Step-by-step explanation:
In this question you'll be trying to find out what x is.
(x-8), this is from the amount of years ago and 2(56-x) is from subtracting 8 with 64 and the 2 came from the fact that Jeremy is twice the age.
(x-8)=2(56-x)
x-8=102-2x
Now we want to have x by itself so we'll add 2x on both sides to remove the -2x from the right side.
3x-8=102 (Add up on both sides)
3x=110 (Divide by 3)
x=36.666
Question 1
cos(C) = adj/hyp
cos(C) = BC/AC
cos(C) = 15/17
Answer: Choice C) 15/17
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Question 2
sin(E) = opp/hyp
sin(E) = FD/DE
sin(E) = 24/25
So angle E is the answer
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Question 3
AC is the adjacent side to the given angle A = 33 degrees
AB = 14 is the hypotenuse
cos(angle) = adjacent/hypotenuse
cos(33) = x/14
14*cos(33) = x
x = 14*cos(33)
x = 11.741
x = 11.7
Answer: 11.7
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Question 4
x = length of board
cos(angle) = adj/hyp
cos(55) = 6/x
x*cos(55) = 6
x = 6/cos(55)
x = 10.46068
x = 10.5
Answer: 10.5
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Question 5
112 is the adjacent side to the given angle 62 degrees
x = height of building, which is the opposite leg
tan(angle) = opp/adj
tan(62) = x/112
112*tan(62) = x
x = 112*tan(62)
x = 210.641364
x = 210.6
Answer: 210.6
Answer:
- <u>59.0891 g (rounded to 4 decimal places)</u>
Explanation:
<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.
Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:
Where:
- A is the amount that remains of the substance after n half-lives have elapses, and
- A₀ is the starting amount of the substance.
In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:
- 330 days / 138 days = 2.3913
Therefore, the amount of polonium-210 that will be left in 330 days is:
Answer:
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Step-by-step explanation: