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Anna35 [415]
3 years ago
13

PLZZ HELP ASAP ILL MAKE U BRAINLIEST

Mathematics
2 answers:
nika2105 [10]3 years ago
8 0
Translation right and down
user100 [1]3 years ago
4 0
Translation right down c=
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The product of two numbers is -30, but their sum is -13. What are these two numbers?
Nata [24]
<h3>Answer:  -15 and 2</h3>

You find this through trial and error.

A much more efficient way is to solve x^2-13x-30 = 0 using the quadratic formula. You'll find the two solutions to be x = 15 and x = -2

Going from those solutions, we get x-15 = 0 and x+2 = 0 which then turn into (x-15)(x+2) = 0 through the zero product property.

3 0
3 years ago
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Can some explain this to me do i need to covert something or can someone explain it to me how in gonna get the answer i try to d
solniwko [45]
Cross multiply:

2.5 ft x 16.5 ft = 41.25 ft

now divide:

41.25 / 8.25 = 5

L = 5 feet 
7 0
3 years ago
6. slope = 9, (-5, 2) no links or bots please
Arada [10]

Answer: y= 9x -5

Step-by-step explanation:

3 0
2 years ago
Find the measure of angle A.
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The measure of angle A is 80
8 0
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Calculate the average travel time for each distance, and then use the results to calculate. A 6-column table with 3 rows in the
BigorU [14]

The average travel time is simply the mean travel time between the given points

  • The average time that it takes for the car to travel the first 0.25m is 2.23s.
  • The average time to travel just between 0.25m and 0.50m is 0.9s.
  • Given the time taken to travel the second 0.25 m section, the velocity would be 0.28m/s.

<u>(a) The average time to travel the first 0.25m</u>

The time travel in the first 0.25m are: 2.24s, 2.21s and 2.23s.

So, the average time to travel is:

Time = \frac{2.24s + 2.21s + 2.23s}{3}

Time = \frac{6.68s}{3}

Time = 2.23s

<u>(b) The average time to travel just between 0.25m and 0.50m</u>

The time travel in the 0.50m are: 3.16s, 3.08s and 3.15s.

So, the average time to travel this distance is:

Time = \frac{3.16s + 3.08s + 3.15s}{3}

Time = \frac{9.39s}{3}

Time = 3.13s

The average time to travel between both distance is the difference between the average time of each distance.

So, we have:

Average = 3.13s - 2.23s

Average = 0.9s

<u>(c) The velocity in the second 0.25m section</u>

The distance and time are:

Distance = 0.25m

Time = 0.9s

So, the velocity is:

Velocity = \frac{Distance}{Time}

This gives

Velocity = \frac{0.25m}{0.9s}

Velocity = 0.28m/s

Read more about distance, velocity and time at:

brainly.com/question/4931057

6 0
2 years ago
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