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ycow [4]
2 years ago
5

Frank is going to the airport. It is 11:43 AM right now. Frank's flight will depart in 2 hours 40 minutes. What is the departure

time of his flight?
Mathematics
1 answer:
Stels [109]2 years ago
5 0
Ok it would be 1:23 p.m. i think

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How do I get the answer for 1 1/2 x 3 x 1 1/9
Mekhanik [1.2K]

\boxed{1 \frac{1}{2}\times 3 \times 1 \frac{1}{9}=5}

<h2>Explanation:</h2>

in this problem we have the following expression:

1 \frac{1}{2}\times 3 \times 1 \frac{1}{9}

So here:

1 \frac{1}{2} \ and \ 1 \frac{1}{9} \ are \ written \ as \ mixed \ fractions

Let's convert them as improper fractions:

1 \frac{1}{2}=1+\frac{1}{2}=\frac{1\times 2+1}{2}=\frac{3}{2} \\ \\ 1 \frac{1}{9}=1+\frac{1}{9}=\frac{1\times9 +1}{9}=\frac{10}{9}

Rewriting our expression:

\frac{3}{2}\times 3 \times \frac{10}{9}=\frac{3\times 3 \times 10}{2\times 9}=\frac{90}{18}=5

<h2>Learn more:</h2>

Simplify: brainly.com/question/10644722

#LearnWithBrainly

3 0
3 years ago
A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
8 0
2 years ago
What is the length of the line segment shown on this coordinate grid?PLEASE HELP :-)
tigry1 [53]
 The line is 4 units in length.
5 0
2 years ago
Will mark brainliest if correct (surface area question)
I am Lyosha [343]

Answer:

535

Step-by-step explanation:

8 x 7 = 56

15 x 17 = 255 .  255 / 2 = 127.5

15 x 17 = 255 .  255 / 2 = 127.5

15 x 7 = 105

17 x 7 = 119

119 + 105 + 127.5 + 127.5 + 56 = 535

6 0
2 years ago
Given: the function defined by f(x)=3x^2-4 Which statement is true? 1. f(0) = 0 2. f(-2) = f(2) 3. f(5)+ f(2) = f(7) 4. f(5) x f
sergeinik [125]
f(x)=3x^2-4 \\ \Downarrow \\ f(0)=3 \times 0^2-4=0-4=-4 \\ -4 \not= 0 \\ f(0) \not= 0 \\&#10;\hbox{statement 1 is false} \\ \\&#10;f(-2)=3 \times (-2)^2-4 =3 \times 4-4=12-4=8 \\&#10;f(2)=3 \times 2^2-4=3 \times 4-4=12-4=8 \\ 8=8&#10;\\ f(-2)=f(2) \\&#10;\hbox{statement 2 is true}

f(5)=3 \times 5^2-4=3 \times 25-4=75-4=71 \\ f(2)=8 \\&#10;f(7)=3 \times 7^2-4=3 \times 49-4=147-4=143 \\&#10;71+8 \not= 143 \\&#10;f(5)+f(2) \not= f(7) \\ \hbox{statement 3 is false} \\ \\&#10;f(5)=71 \\ f(2)=8 \\ f(10)=3 \times 10^2-4=3 \times 100-4=300-4=296 \\&#10;71 \times 8 \not= 296 \\&#10;f(5) \times f(2) \not= f(10) \\&#10;\hbox{statement 4 is false}

Stamement 2. f(-2)=f(2) is true.
3 0
3 years ago
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