The three numbers are 12, 18 and 24
Arithmetic progression
Let the 3 number in arithmetic progression be:
a-d, d, a+d ...
If their sum is 3, then;
a-d+d+a+d = 3
2a + d = 3 ........... 1
If the sum of their squares is 11, then;
(a-d)² + d² + (a+d)² = 11
a²-2ad+d²+d²+a²+2ad+d² 11
2a²+3d² = 11 ....... 2
Solving the equations simultaneously, d = 6 and a = 12
First-term = 12
second term = 18
Thirs term = 24
Hence the three numbers are 12, 18 and 24
Hope this helps you!!!!!! :D
Answer:
=3
Step-by-step explanation:
following the order of operations, whatever is in the parentheses gets done first. so you would add 13 + 2 and get 15. then you would subtract 9-4 and get 5. then you would divide the numbers that you got and get 3.
Answer:
you hgave a 2 and you use 5 and you have to add it and it will be 12 and your answer is 15
Step-by-step explanation:
Answer:
this is not mathmatics
Step-by-step explanation:
