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Rzqust [24]
4 years ago
13

Kelly bought a pair of sneakers for $ 35.00. She also bought a pile of different laces. Each set of laces, L, costs $ 3.00. Writ

e a variable expression to show how Kelly could calculate her total cost
Mathematics
1 answer:
Anika [276]4 years ago
8 0

Answer:

Well Kelly should do L($3.00)+$35.00

The final answer depends upon how many packages of laces she buys.

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Perform the following multiplication<br><br>a) 9xy ( x²y – xy²)<br><br>b) 7 p²q² (9 pq - 9 p²q²)​
erastova [34]

Answer:

hsjishsvdndkssjxbbxjsiaiajbxbxbsjsisis

6 0
3 years ago
$149 guitar; 29% discount​
Vikki [24]
Divide number of guitars by 100% and multiply into discount given



149/100 x 29

1.49 x 29

43.21



$43.21 had been removed

Therefore $105.79 is the guitar cost after discount



Hope it was useful ☻


5 0
4 years ago
5x-3y when x=7 and y=-8
I am Lyosha [343]
5 (7) - 3 (-8)

35 - -24

Because two negatives equal a positive the subtraction sign will change into an addition sign.

35+24

So your answer will be 59.

Hope this helped :)
5 0
3 years ago
Change the subject of the formula L = v 4kt - p to k.
Romashka [77]

Answer:

\boxed{k = \frac{L^2 + p}{4t}}

General Formulas and Concepts:

<u>Algebra I</u>

Basic Equality Properties

  1. Multiplication Property of Equality
  2. Division Property of Equality
  3. Addition Property of Equality
  4. Subtraction Property of Equality

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given.</em>

<em />\displaystyle L = \sqrt{4kt - p}

<u>Step 2: Solve for </u><u><em>k</em></u>
We can use equality properties to help us rewrite the equation to get <em>k</em> as our subject:

Let's first <em>square both sides</em>:

\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}

Next, <em>add p to both sides</em>:

\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}

Next, <em>divide 4t by both sides</em>:

\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}

We can rewrite the new equation by swapping sides to obtain our final expression:

\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow \boxed{k = \frac{L^2 + p}{4t}}\end{aligned}

∴ we have <em>changed</em> the subject of the formula.

---

Learn more about Algebra I: brainly.com/question/27698547

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Topic: Algebra I

6 0
2 years ago
Which of the following graphs correctly displays the data from the table
blagie [28]
A is the correct answer
4 0
3 years ago
Read 2 more answers
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