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4 years ago

Marisol bought 20 peices of ribbion for $18. what would be the cost of 30 peices of ribbon

Mathematics

1 answer:

Hatshy [7]4 years ago

3 0

27 because 18 divided by 2 is 9 so you just add 9 more to $18

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Given AB= BC FINDIND X= AB= BC= AC=

tester [92]

Answer:

see explanation

Step-by-step explanation:

Given AB ≅ BC, then

AB = BC = x + 6 , and

AC = AB + BC ← substitute values

3x - 31 = x + 6 + x + 6, that is

3x - 31 = 2x + 12 ( subtract 2x from both sides )

x - 31 = 12 ( add 31 to both sides )

x = 43

Hence

AB = BC = x + 6 = 43 + 6 = 49

AC = 3x - 31 =(3 × 43) - 31 = 129 - 31 = 98

8 0

3 years ago

A box of Jell-O costs $0.50, and makes 2 cups. How much would it cost to fill a swimming pool 4 feet deep, 8 feet wide, and 12 f

garik1379 [7]

Answer:

$11,520

Step-by-step explanation:

4 * 8 * 12 = 384 cu ft.

384 * 7.5 = 2880 gallons

There are 16 cups in a gallon

2880 * 16 = 46,080 cups

46,080/2 * .50 = $11,520

6 0

3 years ago

A storage shed is to be built in the shape of a box with a square base. It is to have a volume of 686 cubic feet. The concrete f

kobusy [5.1K]

Answer:

Therefore the dimension of box is 7 ft by 7 ft by 14 ft.

Step-by-step explanation:

Given that, a storage shade is be built in the shape of a box with a square base.

Let the height of the box be h and the length of one side of the square base be x.

The area of the square base is = side²

=x²

The volume of the box is = area of the base × height

=x²h

According to the problem,

x²h=686

$\Rightarrow h=\frac{686}{x^2}$ .......(1)

The concrete for the base costs $5 per square foot.

The material for the base costs =$ 5x²

The material for the roof costs $9 per square foot.

The material cost for roof is =$9x²

The material for the sides costs $3.50 per square foot.

The material cost for sides =$(3.50× 4xh )

=$14xh

Total cost =$(5x²+9x²+14xh)

=$(14x²+14 xh)

Let

C = 14x²+14 xh

Putting $h=\frac{686}{x^2}$

$C=14x^2+14 x.\frac{686}{x^2}$

$\Rightarrow C=14x^2+\frac{9604}{x}$

Differentiating with respect to x

$C'= 28x-\frac{9604}{x^2}$

Again differentiating with respect to x

$C''= 28+\frac{19208}{x^2}$

To find the dimension set C'=0

$28x-\frac{9604}{x^2}=0$

$\Rightarrow 28x=\frac{9604}{x^2}$

$\Rightarrow x^3=\frac{9604}{28}$

$\Rightarrow x=7$

Now,

$C''|_{x=7}= 28+\frac{19208}{7^2}>0$

Since at x=7, C''>0, So at x=7 , The cost of material will be minimum.

The height of the box is $h=\frac{686}{x^2}$

$=\frac{686}{7^2}$

=14 foot

Therefore the dimension of box is 7 ft by 7 ft by 14 ft.

The cost of the material is $=14x^2+\frac{9604}{x}$

$=14(7)^2+\frac{9604}{7}$

=$2,058

6 0

3 years ago

What value of x makes the equation true? −4(x−3)=−28

Vesnalui [34]

Answer:

x = 10.

Step-by-step explanation:

First we must divide both sides by -4, and we get x - 3 = 7. Then we add 3 to both sides and get x = 10.

3 0

2 years ago

Read 2 more answers

4/17 as a decimal i need help how to divide and make this a decimal

allsm [11]

Answer:

4/17 is irreducible and is a irrational decimal number 0.23529411764705882352941176470588235294117647058823529411764705882352941176470588235294117647058823529411764705882...

Step-by-step explanation:

8 0

3 years ago