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DIA [1.3K]
3 years ago
10

Marisol bought 20 peices of ribbion for $18. what would be the cost of 30 peices of ribbon

Mathematics
1 answer:
Hatshy [7]3 years ago
3 0
27 because 18 divided by 2 is 9 so you just add 9 more to $18
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Water flows through a pipe at a rate of 2 liters every 3.5 seconds
Veronika [31]

Answer:

whats the rest of the problem

7 0
3 years ago
Which compound most likely contains polar covalent bonds?<br> NaCl<br> AlF3<br> Br2<br> NF3
belka [17]

Answer: The correct answer is NF_3

Explanation:

In NF_3 molecule, there are three bond pairs and one lone pair present in the molecule. In a molecule, lone pair present on the nitrogen atom will have a dipole moment in upward direction where as total dipole moment formed by three fluorine atoms will be more in magnitude and it will be directed in downward direction which means that the net dipole moment will be in downward direction. As shown in image attached.

Hence, covalent bond present between nitrogen and fluorine will become polar in nature.

So, the correct answer is NF_3.

7 0
2 years ago
Read 2 more answers
Plz Answer this question ASAP!
nydimaria [60]

Answer:

564 tiles

Step-by-step explanation:

there are many ways to solve this soo...

1. convert to centimetres (there are 100 centimetres in 1 metre)

2. the square tiles area = 20*20=400cm

2. find the large area (4.8m x 3.8m or 480cm x 380cm)

480 *380=182400cm

2. find the two smaller areas (1.2m x 1.8m or 120cm x 180cm)

2(120*180)=4.3200cm

3. add to find total area

182400 +43200=225600cm

4. find how many tiles are needed

\frac{225600}{400}= 564 tiles

8 0
2 years ago
Kelly and Daniel wrote the following proofs to prove that vertical angles are congruent. who is correct?
katrin [286]
Kelly? Im not sure actually... Im going with Kelly but im probably wrong
7 0
3 years ago
Read 2 more answers
Denise is a professional swimmer who trains, in part, by running. she would like to estimate the average number of miles she run
SSSSS [86.1K]
Given:
n = 20, sample size
xbar = 17.5, sample mean
s = 3.8, sample standard deiation
99% confidence interval

The degrees of freedom is 
df = n-1 = 19

We do not know the population standard deviation, so we should determine t* that corresponds to df = 19.
From a one-tailed distribution, 99% CI means using a p-value of 0.005.
Obtain
t* = 2.8609.

The 99% confidence interval is
xbar +/- t*(s/√n)

t*(s/√n) = 2.8609*(3.8/√20) = 2.4309
The 99% confidence interval is
(17.5 - 2.4309, 17.5 + 2.4309) = (15.069, 19.931)

Answer: The 99% confidence interval is (15.07, 19.93)
4 0
3 years ago
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