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soldi70 [24.7K]
3 years ago
9

Suppose your statistics professor reports test grades as​ z-scores, and you got a score of 2.49 on an exam. ​(a) Write a sentenc

e explaining what that means. ​(b) Your friend got a​ z-score of negative 2−2. If the grades satisfy the Nearly Normal​ Condition, about what percent of the class scored lower than your​ friend? ​
Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0

Answer:

a) A z-score of 2.49 means that your grade was 2.49 standard deviations above the mean of all grades.

b) 1.39% of the class scored lower than your​ friend.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

You got a score of 2.49 on an exam. ​

(a) Write a sentence explaining what that means

A z-score of 2.49 means that your grade was 2.49 standard deviations above the mean of all grades.

(b) Your friend got a​ z-score of negative 2−2. If the grades satisfy the Nearly Normal​ Condition, about what percent of the class scored lower than your​ friend? ​

This percentage is the pvalue of Z = -2.2

So 0.0139 = 1.39% of the class scored lower than your​ friend.

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4 0
3 years ago
Find the complex fourth roots of 81(cos(3pi/8) + i sin(3pi/8))
BartSMP [9]
By using <span>De Moivre's theorem:
</span>
If we have the complex number ⇒ z = a ( cos θ + i sin θ)
∴ \sqrt[n]{z} =  \sqrt[n]{a} \ (cos \  \frac{\theta + 360K}{n} + i \ sin \ \frac{\theta +360k}{n} )
k= 0, 1 , 2, ..... , (n-1)


For The given complex number <span>⇒ z = 81(cos(3π/8) + i sin(3π/8))
</span>

Part (A) <span>find the modulus for all of the fourth roots
</span>
<span>∴ The modulus of the given complex number = l z l = 81
</span>
∴ The modulus of the fourth root = \sqrt[4]{z} =  \sqrt[4]{81} = 3

Part (b) find the angle for each of the four roots

The angle of the given complex number = \frac{3 \pi}{8}
There is four roots and the angle between each root = \frac{2 \pi}{4} =  \frac{\pi}{2}
The angle of the first root = \frac{ \frac{3 \pi}{8} }{4} =  \frac{3 \pi}{32}
The angle of the second root = \frac{3\pi}{32} +  \frac{\pi}{2} =  \frac{19\pi}{32}
The angle of the third root = \frac{19\pi}{32} +  \frac{\pi}{2} =  \frac{35\pi}{32}
The angle of the  fourth root = \frac{35\pi}{32} +  \frac{\pi}{2} =  \frac{51\pi}{32}

Part (C): find all of the fourth roots of this

The first root = z_{1} = 3 ( cos \  \frac{3\pi}{32} + i \ sin \ \frac{3\pi}{32})
The second root = z_{2} = 3 ( cos \  \frac{19\pi}{32} + i \ sin \ \frac{19\pi}{32})

The third root = z_{3} = 3 ( cos \  \frac{35\pi}{32} + i \ sin \ \frac{35\pi}{32})
The fourth root = z_{4} = 3 ( cos \  \frac{51\pi}{32} + i \ sin \ \frac{51\pi}{32})
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The correct option is (B) show that Mrs. Deverell continues to be diminished in her new home.

<h3>What does line 73 described?</h3>

In line 73, the author compares Mrs. Deverell to an "intimidated child" primarily in order to -

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  • The author utilizes the metaphor of a scared child in this situation.
  • As a result, this analogy conveys to the reader Mrs. Deverell's limited status in her new home.

Therefore, according to the writer; in the line 73 the best description for the intimidated child is shown by option B.

To know more about the child, here

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