Answer:
D
Step-by-step explanation:
i think so but it will help you
Using: A^2+b^2=c^2
A&b= (√10)^2=10
10+10=c^2
20=c^2
(take the square root of 20)
c=2√5
Your answer is D
Answer:
x = 2 so y = 7
x = 4 so y = 11
Step-by-step explanation:
y = 2x + 3
x = 0 so y = 2(0) + 3 | y = 3
x = 2 so y = 2(2) + 3 | y = 7
x = 4 so y = 2(4) + 3 | y = 11
x = 6 so y = 2(6) + 3 | y = 15
So.... notice the picture below
now, we know what the "height" or "altitude" is
now, we also know the perimeter is 18cm
so, k + k + b = 18
or 2k + b = 18
thus

so... one can say that

and you can simplify it if you wish.. not sure you have to
Answer:

Step-by-step explanation:
The Universal Set, n(U)=2092


Let the number who take all three subjects, 
Note that in the Venn Diagram, we have subtracted
from each of the intersection of two sets.
The next step is to determine the number of students who study only each of the courses.
![n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x](https://tex.z-dn.net/?f=n%28S%5C%3Aonly%29%3D1232-%5B103-x%2Bx%2B23-x%5D%3D1106%2Bx%5C%5Cn%28F%5C%3A%20only%29%3D879-%5B103-x%2Bx%2B14-x%5D%3D762%2Bx%5C%5Cn%28R%5C%3Aonly%29%3D114-%5B23-x%2Bx%2B14-x%5D%3D77%2Bx)
These values are substituted in the second Venn diagram
Adding up all the values
2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]
2092=2085+x
x=2092-2085
x=7
The number of students who have taken courses in all three subjects, 