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2 years ago

Indicate the equation of the given line in standard form, in the equation box below.

1 answer:

6 0

Perpendicular lines have slopes that are negative reciprocals of each other, so the equation of the line in point-slope form is:

$y-4=-\frac{5}{2}(x+3)$

Rewriting this in standard form,

$2y-8=-5(x+3) \\ \\ 2y-8=-5x-15 \\ \\ \boxed{5x+2y=-7}$

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What is 32 divided by 608

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19 you could’ve just used the calculator lol

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2 years ago

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Any help would be appreciated. Thank you!

trapecia [35]

Answer:

Area $=62.5\sqrt{6}$ square units

$AB=5\sqrt{15}$ units

$BC=5\sqrt{10}$ units

Step-by-step explanation:

In a right triangle the altitude drawn to the hypotenuse is the geometric mean of the segments at which this altitude divides the hypotenuse.

So,

$BD^2=15\cdot 10\\ \\BD^2=150\\ \\BD=\sqrt{150}=5\sqrt{6}\ units$

a. The area of the triangle ABC is

$A_{ABC}=\dfrac{1}{2}\cdot BD\cdot AC=\dfrac{1}{2}\cdot 5\sqrt{6}\cdot (15+10)=\dfrac{125\sqrt{6}}{2}=62.5\sqrt{6}\ un^2.$

b. The legs of the right triangle are geometric means of the segment adjacent to this leg and the hypotenuse, so

$AB^2=AD\cdot AC=15\cdot 25\Rightarrow AB=5\sqrt{15}\ units\\ \\BC^2=CD\cdot AC=10\cdot 25\Rightarrow BC=5\sqrt{10}\ units$

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3 years ago

Simplify 7x+42/x^2+13x+42

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2(10x^3+21x^2+21
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