Answer:
I think it’s the first one, A
Answer:
good news, the second one is relatively easy because it can be factored to (2x+1)(2x-3) which means that number two has solutions of -1/2 and 3/2
but for number one you have to either use the quadratic equation cause I've tried using synthetic division or just use the second equation to derive the first solutions so I tried move the graph up by two units and found that the intercepts are approximately (1+-√2)/2 or 1/2+-1/√2 for 4x^2-4x-1
The formula of the future value of annuity due is
A=p [(1+r/k)^(kn)-1)/(r/k)]×(1+r/k)
A future value of annuity due
P payment 125
R interest rate 0.0375
K compounded monthly 12
N time 8 years
Solve for A
A=125×(((1+0.0375÷12)^(12
×8)−1)÷(0.0375÷12))×(1
+0.0375÷12)
=14,012.75
X=2
Y=4
Multiply top so y values cancel out, so multiple top by -3. Y values cancel out. You combine top and bottom equations, x=2. Plug 2 in first equation for x. Y=4
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