Nucleotides are a base pair and they fit together because their shape allows them to bond. The A-T pair frames two hydrogen bonds. G-C forms 3. As the strands bond they hold the Base Pairs of DNA together
I don't see anything but I know that what you might be talking about goes like this...
Domain, Kingdom, Phylum, Class. Order, Family, Genus, species.
Hope this helped!
I found the attached image on the internet and it really helps complete this exercise.
First question:
In the presence of an enzyme, the course of the reaction is shown by the
red curve. The necessary energy to make a reaction occur is less when there is an enzyme to help the reaction happen. Enzymes work as catalysts that act over substrates converting them into different molecules in a much accelerated way then it would happen without the enzyme's help, if it would happen at all.
Second question:
The activation energy is represented by
line B. The activation energy is the energy needed to be available for a reaction to happen. If we compare it with line A, which represents the activation energy necessary for a reaction without an enzyme, we can see how much less energy is necessary to dispend when an enzyme is part of the reaction. Line C represents the energy resultant from the reaction.
Answer:
Explanation:
The Genotype of the woman is XCbXN
The man XNY
Since the allele for the color blindness is carried on one of the X -chromosomes of the carrier mother, then the male children will be color blind or carrier deopending on the defective gene they inherited. Since they will receive the defective or normal allele from the mothers,but the female will carriers or normal because they will inherit either defective allele or normal allele from the mother,but normal X allele from the father.
Assuming the colorbind gene was inherited by One of the boys, and the girls take the defective genes
1. XNY vs XCbXN.Then the one of the boys will be colorblind and the one of girls will be carriers. XNXCb, XNXN, XCbY,XNY 50 %
2.If the two boys take the effective genes from the mothers. and none of the girls take the defective alelle
Then the two boys will be colorblind and the girls will be carrries XcbY,XcbY and XNXN XNXN.(normal girls).
The proportions that will be the females since the girls can only take the defective allele from one of the normal and defective allele from the mother. Assuming the girls take the defective allele from the mothers and take normal from the father,they will all be carriers,since the X of the father is normal.
They can not have a color blind girl.Since the father is normal It takes two colorblind X-chromosome to give a girl.