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Harlamova29_29 [7]
3 years ago
14

In bacterial cell walls a. peptides form crosslinks between polysaccharides b. polysaccharides form nonspecific mixtures with pr

oteins c. oligosaccharides form crosslinks between proteins d. polysaccharides are hydrogen bonded together
Biology
1 answer:
vitfil [10]3 years ago
4 0

Answer:

the correct option is A "peptides form crosslinks between polysaccharides"

Explanation:

The bacterial wall of bacteria is made up of a complex peptide that is called peptidoglycan, which in turn is intertwined with polysaccharides and many more structures such as protein, this wall is confined or has the function of being able to protect the osmotic balance of the bacteria so that it does not go into failure and does not lose vitality. If the wall breaks, the bacteria goes into osmotic shock and dies, which is why this was a great discovery, because although it is very difficult to pass through antibiotics or antiseptics, once the porification of this wall is generated, the osmotic balance is lost and bactericidal power is acquired.

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Which curve shows the course of the reaction in the presence of an enzyme--the black curve or the red curve? Which line represen
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I found the attached image on the internet and it really helps complete this exercise.

First question:
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Second question:
The activation energy is represented by line B. The activation energy is the energy needed to be available for a reaction to happen. If we compare it with line A, which represents the activation energy necessary for a reaction without an enzyme, we can see how much less energy is necessary to dispend when an enzyme is part of the reaction. Line C represents the energy resultant from the reaction.

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A woman who is a carrier for colour blindness (X-linked recessive) has children with a man who has normal colour vision. A. What
viva [34]

Answer:

Explanation:

The Genotype of the  woman is XCbXN

The man XNY

Since the allele for the color blindness is carried on one of the X -chromosomes of the  carrier mother, then  the male children will be color blind or carrier deopending on the defective gene they inherited. Since they will receive the defective or normal  allele from the  mothers,but the female will carriers or normal because they will inherit either defective allele or normal allele from the mother,but normal  X allele from the father.

Assuming the colorbind gene was inherited by One of the boys, and the girls take the defective genes

1. XNY vs XCbXN.Then the one of the  boys will be colorblind  and the one of  girls will be carriers. XNXCb, XNXN, XCbY,XNY  50 %

2.If the two boys take the effective genes from the mothers. and none of the girls take the defective alelle

Then the two boys will be colorblind and the girls will be carrries XcbY,XcbY and XNXN XNXN.(normal girls).

The proportions that will be  the females  since the girls can only take the defective allele from one of the normal and defective allele from the mother. Assuming the girls  take the defective allele from the mothers and take normal from the father,they will all  be carriers,since the X of the father is normal.

They can not have a color blind girl.Since the father is normal It takes two colorblind X-chromosome to give a girl.

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3 years ago
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