Question

If 35.0 g of CH3OH (MM = 32.0 g/mol) are dissolved in 500.0 mL of solution, what is the concentration of CH3OH in the solution?​

Answer 1

The concentration of CH3OH in the solution is 2.18M

HOW TO CALCULATE MOLARITY:

• The molarity of a solution can be calculated by dividing the number of moles by its volume as follows:

• Molarity {M} = no. of moles (mol) ÷ volume (L)

• According to this question, 35.0 g of CH3OH (MM = 32.0 g/mol) are dissolved in 500.0 mL of solution. The number of moles of methanol is calculated as follows:

no. of moles = 35g ÷ 32g/mol

no. of moles = 1.09mol

• Molarity = no. of moles ÷ volume

Volume = 500mL = 0.500L

Molarity = 1.09mol ÷ 0.500L

Molarity = 2.18M

Therefore, the concentration of CH3OH in the solution is 2.18M

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