The concentration of CH3OH in the solution is 2.18M
HOW TO CALCULATE MOLARITY:
The molarity of a solution can be calculated by dividing the number of moles by its volume as follows:
Molarity {M} = no. of moles (mol) ÷ volume (L)
According to this question, 35.0 g of CH3OH (MM = 32.0 g/mol) are dissolved in 500.0 mL of solution. The number of moles of methanol is calculated as follows:
no. of moles = 35g ÷ 32g/mol
no. of moles = 1.09mol
Molarity = no. of moles ÷ volume
Volume = 500mL = 0.500L
Molarity = 1.09mol ÷ 0.500L
Molarity = 2.18M
Therefore, the concentration of CH3OH in the solution is 2.18M
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