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3 years ago

Solve the equation for the stated variable: A=1/2ap. Solve for p

1 answer:

8 0

Hello,

<span>A=1/2ap
</span>
Solve for p:

Solution:

solve for p by simplifying both sides of the equation , then isolating the variable.

p=2A/a

Faith xoxo

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tabita bought peppers that cost 0.79 per pound she paid 3.95 for the peppers how many pounds did she buy

RUDIKE [14]

Answer:

237

Step-by-step explanation:

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4 years ago

$3/min multiplied by blank equals to blank dollars/ 1 hour. <br><br> Help, please I need the answer!

Zinaida [17]

I believe it would be $180

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4 years ago

The area of a rectangle is 135 square feet. The width is 6 feet less than the length. Find the dimensions of the rectangle

drek231 [11]

The length is 15 inches and width is 9 inches

Step-by-step explanation:

Let

l be the length

and

w be the width

w = l-6

The area of rectangle is 135 ft^2

The formula for area is:

$Area=l*w\\135=l*(l-6)\\135=l^2-6l\\l^2-6l-135=0\\l^2+9l-15l-135=0\\l(l+9)-15(l+9)=0\\(l+9)(l-15)=0\\l+9 = 0 => l=-9\\l-15 = 0 => l=15\\$

As the length cannot be negative, so we will use the value of length 15

If length 15,

w=l-6

w=15-6

w=9

So,

The length is 15 inches and width is 9 inches

Keywords: Area of rectangle, Quadratic equation

Learn more about quadratic equation at:

#LearnwithBrainly

7 0

3 years ago

The functions q and r are defined as follows

kolezko [41]

Answer:

Step-by-step explanation:

So we have the two functions:

$g(x)=-2x-2\text{ and } r(x)=x^2-2$

And we want to find the value of r(g(4)).

To do so, first find the value of g(4):

$g(x)=-2x-2\\g(4)=-2(4)-2\\$

Multiply:

$g(4)=(-8)-2$

Subtract:

$g(4)=-10$

Now, substitute this into r(g(4)):

$r(g(4))\\=r(-10)$

And substitute this value into r(x):

$r(-10)=(-10)^2-2$

Square:

$r(-10)=100-2$

Subtract:

$r(-10)=98$

Therefore:

$r(-10)=r(g(4))=98$

3 0

3 years ago

There is an antenna on the top of a building. From a location 300 feet from the base of the building, the angle of elevation to

san4es73 [151]

Answer:

Height of the antenna = 28 ft (Approx)

Given:

Length of base = 300 ft

Angle of elevation to the building = 40°

Angle of elevation to the antenna = 43°

Find:

Height of the antenna

Computation:

Using trigonometry function:

Tan40° = Height of building / Length of base

Height of building = 251.73 ft

Tan43° = [Height of building + Height of the antenna] / Length of base

0.9325 = [251.73 + Height of the antenna] / 300

Height of the antenna = 28.02 ft

Height of the antenna = 28 ft (Approx)

5 0

3 years ago