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3 years ago

Please help me due at tomorrow 8a.m please

Mathematics

2 answers:

eimsori [14]3 years ago

7 0

Answer:

Step-by-step explanation:

You do the slope formula

(y2 - y1)/(x2-x1)

you get 15/2 which is 7.5

laiz [17]3 years ago

3 0

Answer:

Step-by-step explanation:

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Find the range of the data.<br> 73, 69, 78, 68, 70, 86, 80, 72<br> The range is

Fiesta28 [93]

The answer is 18.

Work:
[i]The range is the gap between the smallest value and the largest value. [/i]

The smallest is 68.
The largest is 86.
The gap between them is 86-68=18.

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3 years ago

Read 2 more answers

On Monday there are 25 pencils in a basket, If 3 pencils are taken out of the basket each day, how many pencils are left in the

lutik1710 [3]

13 cuz add 4 days then friday so 4×3 which is 12 and 12-25 so ye its 13

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2 years ago

Set up but do not solve for the appropriate particular solution yp for the differential equation y′′+4y=5xcos(2x) using the Meth

taurus [48]

Answer:

So, solution of the differential equation is

$y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

Step-by-step explanation:

We have the given differential equation: y′′+4y=5xcos(2x)

We use the Method of Undetermined Coefficients.

We first solve the homogeneous differential equation y′′+4y=0.

$y''+4y=0\\\\r^2+4=0\\\\r=\pm2i\\\\$

It is a homogeneous solution:

$y_h(t)=c_1e^{-2i t}+c_2e^{2i t}$

Now, we finding a particular solution.

$y_p(t)=A5x\cos 2x\\\\y'_p(t)=A5\cos 2x-A10x\sin 2x\\\\y''_p(t)=-A20\sin 2x-A20x\cos 2x\\\\\\\implies y''+4y=5x\cos 2x\\\\-A20\sin 2x-A20x\cos 2x+4\cdot A5x\cos 2x=5x\cos 2x\\\\-A20\sin 2x=5x\cos 2x\\\\A=-\frac{x}{4} \cot 2x\\$

we get

$y_p(t)=A5\cos 2x\\\\y_p(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x\\\\\\y(t)=y_p(t)+y_h(t)\\\\y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

So, solution of the differential equation is

$y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

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3 years ago

Help please thanks so much

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