The equation of the hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0) is 
<h3>How to determine the equation of the hyperbola?</h3>
The given parameters are:
- Directrices at x = ±2 
- Foci at (5, 0) and (−5, 0)
The foci of a hyperbola are represented as:
Foci = (k ± c, h)
The center is:
Center = (h,k)
And the directrix is:
Directrix, x = h ± a²/c
By comparison, we have:
k ± c = ±5
h = 0
h ± a²/c = ±2
Substitute h = 0 in h ± a²/c = ±2
0 ± a²/c = ±2
This gives
a²/c = 2
Multiply both sides by c
a² = 2c
k ± c = ±5 means that:
k ± c = 0 ± 5
By comparison, we have:
k = 0 and c = 5
Substitute c = 5 in a² = 2c
a² = 2 * 5
a² = 10
Next, we calculate b using:
b² = c² - a²
This gives
b² = 5² - 10
Evaluate
b² = 15
The hyperbola is represented as:

So, we have:

Evaluate

Hence, the equation of the hyperbola is 
Read more about hyperbola at:
brainly.com/question/3405939
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7. the last one 
I = P R T 
I = 15.75 P = 500 R = unknown T = 6
15.75 = 500 (r) (6) 
divide the T and I
15.75 ÷ 6 = 500 (r) (6) ÷6
2.62 = 500 (r) *get rid of the six*
divide the P with new answer 
2.62 ÷ 500 = 500 ÷ 500 *get rid of 500*
0.00524 = r
move decimal to make it in to a percentage 
5.24% = R 
        
             
        
        
        
Answer:
Step-by-step explanation:
The Pythagorean theorem is sqrt(a^2 + b^ 2) = c, so:
sqrt(22^2 + 8^2) = c
sqrt(548) = c
23.41 = c
 
        
             
        
        
        
Answer:
The answer is to the question is 13