<span>Considering that Seth travels with constant speed <span><span>v=<span>dt</span></span><span>v=<span>dt</span></span></span>, then <span><span>v=<span>157.1</span>=<span>x3600</span></span><span>v=<span>157.1</span>=<span>x3600</span></span></span> where <span>xx</span> is the distance traveled in 1 hour. So his velocity would be x miles/hour. By computing <span><span>x=<span><span>3600⋅1</span>57.1</span>=63.047</span><span>x=<span><span>3600⋅1</span>57.1</span>=63.047</span></span>, thus Seth travels at a speed of <span><span>63.047miles/hour</span><span>63.047miles/hour</span></span></span>
Answer:
The vertex is (6,-5)
the axis of symmetry is x = 6
Answer:
-2/3, -0.6, 0.2, 1/2, 5/8
Step-by-step explanation:
What you do is you have to make them into decimals.
-0.6 and 0.2 are already in decimals.
-2/3 as a decimal is -0.667
1/2 as a decimal is 0.5
5/8 as a decimal is 0.625
-2/3, -0.6, 0.2, 1/2, 5/8 is your answer.
Symmetry can be determined visually in a graph. If both graphs are mirror-image of each other, then both of the equations are symmetric. But, you can also determine it analytically through testing the symmetry. These are the rules:
If
f(r, θ) = f(r,-θ), symmetric to the polar axis or the x-axis
f(r, θ) = f(-r,θ), symmetric to the y-axis
f(r, θ) = f(-r,-θ), symmetric to the pole or the origin
Test for symmetry about the x-axis
f(r,θ): r=4 cos3θ
f(r,-θ): r = 4 cos3(-θ) ⇒ r = 4 cos3θ
∴The graph is symmetric about the x-axis.
Test for symmetry about the y-axis
f(r,θ): r=4 cos3θ
f(-r,θ): -r = 4 cos3θ
∴The graph is not symmetric about the y-axis.
Test for symmetry about the origin
f(r,θ): r=4 cos3θ
f(-r,-θ): -r = 4 cos3(-θ) ⇒ r = -4 cos3θ
∴The graph is not symmetric about the origin.
Answer:
The equation of the line is y - 12 = (x + 9) ⇒ B
Step-by-step explanation:
The slope-point form of the linear equation is
y - y1 = m(x - x1), where
- m is the slope of the line
- (x1, y1) are the coordinates of a point lie on the line
∵ The slope of a line is
∴ m =
∵ The line passes through point (-9, 12)
∴ x1 = -9 and y1 = 12
→ Substitute these values in the form of the equation above
∵ y - 12 = (x - -9)
→ Remember (-)(-) = (+)
∴ y - 12 = (x + 9)
∴ The equation of the line is y - 12 = (x + 9)