Answer:
a= 200
b = 210
Step-by-step explanation:
My assumption is, we have to find the length of sides of rectangle
Given
perimeter = 2a + 2b = 820 ft (i) (here a is smaller side and b is larger side)
area = a*b = 42,000 ft^2 (ii)
from eq (1)
2a + 2b = 820
=> 2(a+b) = 820
=> a+b = 820/2
=> a + b = 410
=> a = 410-b (iii)
putting the value of a in eq(ii), we get
(410-b) *b = 42,000
410b - b^2 = 42,000
0 = b^2 - 410b + 42000
b^2 - 410b + 42000 = 0
b^2- 200b- 210b + 42000 = 0
b(b-200)-210(b-200) = 0
(b-200)(b-210) = 0
or
b= 210 and b = 200
if b is larger side than b =210
By putting value of b in eq(iii),
a = 410 -210 = 200
Answer with Step-by-step explanation:
We are given that:
tanA = 0.45
tanA= 
= 
⇒
=0.45
⇒
=
⇒
=
⇒ AC= 20
Hence, by pythagoras theorem
AB²=AC²+BC²
AB²=20²+9²
AB²=481
⇒ AB=21.9 units
Hence, the approximate length of AB is:
22 units
Answer:
subtract 0.88 from 2.07 and then from that divide the answer by 0.17
Step-by-step explanation:
cross multiply
2x - 4 = 4 × 5
2x - 4 =20
collect like terms (CLT)
2x = 20 + 4
2x=24
divide both sides by 2
x=12
First equal the equation to f(x) or y
f(x)= (x²+x-2)÷(x²-3x-4)
To find y-intercept, x coordinates have to be 0
f(0)=(0²+0-2)÷(0²-3(0)-4)
f(0)=-2/-4
f(0)=1/2 (y-intercept)
To find x-intercept, make y=0
0=(x²+x-2)÷(x²-3x-4)
0((x²-3x-4)=(x²+x-2)
0=x²+x-2
0=(x-1)(x+2)
x-1
x-1=0
x=1
x+2=0
x=-2
The x-intercepts would be 1, -2
Hope I helped :)