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avanturin [10]
3 years ago
9

Solve by substitution, elimination, or graphing. Show your work.

Mathematics
1 answer:
Flura [38]3 years ago
4 0
1. 3t + 2b = 16....multiply by -3
    5t + 3b = 25...multiply by 2
   ----------------
    -9t - 6b = -48 (result of multiplying by -3)
    10t + 6b = 50 (result of multiplying by 2)
  ---------------- add
   t = 2

3t + 2b = 16
3(2) + 2b = 16
2b = 10
b = 5

so tacos (t) cost $ 2 and burritos (b) cost $ 5
===================
d + q = 75......d = 75 - q
0.10d + 0.25q = 10.95

0.10(75 - q) + 0.25q = 10.95
7.50 - 0.10q + 0.25q = 10.95
0.15q = 3.45
q = 23....so there are 23 quarters
=====================
x = 2 point shots, y = 3 point shots
x + y = 24.....multiply by -2
2x + 3y = 54
----------------
-2x - 2y = -48 (result of multiplying by -2)
2x + 3y = 54
----------------add
y = 6.......so there was 6 three point shots

x + y = 24
x + 6 = 24
x = 18......and 18 two point shots
======================
5.50g + 5 = 2.50g + 17
5.50g - 2.50g = 17 - 5
3g = 12
g = 4......they will cost the same with 4 game rentals
less then 4 rentals, use Fun Guys....more then 4, use Game Bank
=======================
(2,5)(4,9)
slope = (9 - 5) / (4 - 2) = 4/2 = 2

y = mx + b
slope(m) = 2
(2,5)...x = 2 and y = 5
now sub and find b, the y int
5 = 2(2) + b
5 = 4 + b
5 - 4 = b
1 = b
so ur equation is : y = 2x + 1 (line A)

(0,5)(3,8)
slope = (8 - 5) / (3 - 0) = 3/3 = 1

y = mx + b
slope(m) = 1
(0,5)...x = 0 and y = 5
now sub
5 = 1(0) + b
5 = b
so ur equation is : y = x + 5 (line B)

y = 2x + 1
y = x + 5

2x + 1 = x + 5
2x - x = 5 - 1
x = 4

y = 2x + 1
y = 2(4) + 1
y = 8 + 1
y = 9
so they will meet at (4,9)
=====================
sorry..not 100% sure about the bonus

    
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Answer:

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--------------- = -------------

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g100num [7]

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And we have a normal distribution, so we have a gaussian bell.

We will have that the peak of our bell is at the value x =  1.1

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never [62]
<h3>1 Answer: v = -130</h3>

=============================================================

Explanation:

Because we're given multiple choices to pick from, we can go through each to do trial and error.

For instance, if v = 52, then

v/13 < -7

52/13 < -7

4 < -7

but that's a false statement since 4 is not smaller than -7. Use a number line to see this. You should have -7 to the left of 4, showing that -7 is the smaller value.

Because 4 < -7 is false, this means v/13 < -7 is false when v = 52. This rules out v = 52. You should find that v = 26 and v = -39 won't work for similar reasons.

Only v = -130 works since...

v/13 < -7

-130/13 < -7

-10 < -7

This is true because -10 is to the left of -7 on the number line.

-------------------------------------------------

Another approach:

We have some unknown number v, and we're dividing by 13 to get the expression v/13. To undo this, we multiply both sides by 13

v/13 < -7

13*(v/13) < 13*(-7) .... multiply both sides by 13

v < -91

So any solution to the original inequality must be smaller than -91. This allows us to rule out v = 52, v = 26 and v = -39.

The value v = -130 is smaller than -91, so it satisfies v < -91. Therefore, v = -130 is a solution to the original inequality.

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Answer:

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Step-by-step explanation:

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