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Svet_ta [14]
3 years ago
5

Chapter 5, Review Exercise 11 (5 points) One term, about 700 Statistics 2 students at the University of California, Berkeley, we

re asked how many college mathematics courses they had taken, other than Statistics 2. The average number of courses was about 1.1; the SD was about 1.5. Would the histogram for the data look like (i), (ii), or (iii)
Mathematics
1 answer:
g100num [7]3 years ago
8 0

Answer:

The histograms are missing, but ill try to answer it nonetheless.

Here we have that the standard deviation is bigger than the mean, this means that we will not see one of the ends (the smaller one) of our bell.

And we have a normal distribution, so we have a gaussian bell.

We will have that the peak of our bell is at the value x =  1.1

The histogram will start with a kinda high value at x = 0, it will get to the maximum at x = 1.1 and it will decrease as a normal bell, and knowing that the distance between the mean value and the point where the bell almost is almost zero, is equal to 3 standard deviations, we can expect to see this at x = 1.1 + 3*1.5 = 1.1 + 4.5 = 5.6

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The average reading speed of students completing a speed-reading course is 435 words per minute (wpm). If the standard deviation
nekit [7.7K]

Answer:

a)

Z = -1.58

Z = -1.58 means that a reading speed of 340 wpm is 1.58 standard deviations below the mean reading speed.

b)

Z = 0.67

Z = 0.67 means that a reading speed of 475 wpm is 0.67 standard deviations above the mean reading speed.

c)

Z = -0.25

Z = -0.25 means that a reading speed of 420 wpm is 0.25 standard deviations below the mean reading speed.

d)

Z = 2.92

Z = 2.92 means that a reading speed of 610 wpm is 2.92 standard deviations above the mean reading speed.

Step-by-step explanation:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The z-score measures how many standard deviations a measure X is above or below the mean.

In this problem, we have that:

\mu = 435, \sigma = 60

a. 340 wpm

Z = \frac{X - \mu}{\sigma}

Z = \frac{340 - 435}{60}

Z = -1.58

Z = -1.58 means that a reading speed of 340 wpm is 1.58 standard deviations below the mean reading speed.

b. 475 wpm

Z = \frac{X - \mu}{\sigma}

Z = \frac{475 - 435}{60}

Z = 0.67

Z = 0.67 means that a reading speed of 475 wpm is 0.67 standard deviations above the mean reading speed.

c. 420wpm

Z = \frac{X - \mu}{\sigma}

Z = \frac{420 - 435}{60}

Z = -0.25

Z = -0.25 means that a reading speed of 420 wpm is 0.25 standard deviations below the mean reading speed.

d. 610wpm

Z = \frac{X - \mu}{\sigma}

Z = \frac{610 - 435}{60}

Z = 2.92

Z = 2.92 means that a reading speed of 610 wpm is 2.92 standard deviations above the mean reading speed.

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$2.80 but if rounded to the nearest penny that would be $3.00. Hope this helps!

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Answer:

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Step-by-step explanation:

Because Zachary earns $5 per hour, and he makes a $20 bonus.

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