The formula for gravitational potential energy is Ep= mgh. Lets convert 594 km into m: 594 x 1,000 = 594,000 m. So we do: Ep= (1,800kg)(9.8N/kg)(594,000m) = (17,640N)(594,000) = 10,478,160,000 J.
The answer is B. It is the same..... hope this helps!
Answer:
Vs = 6.73 m/s or Vs = 16.3 m/s
Explanation:
frequency of the trains whistle (f) = 1.64 x 10^{2} Hz = 164 Hz
frequency of beats heard = 4 beats/s = 4 Hz
velocity of the stationary train (Vr) = 0
velocity of sound in air (V) = 343 m/s
velocity of the moving train (Vs) = ?
we can get the velocity of the moving train from the formula below
Fn = f x
...equation 1
where Fn = net frequency
- case one - assuming the train is approaching the station Fn = 164 + 4 = 168 Hz
substituting the known values into equation 1
168 = 164 x
1.02 =
Vs =
Vs = 6.73 m/s
- case two - assuming the train is leaving the station Fn = 164 - 4 = 160 Hz
substituting the known values into equation 1
168 = 160 x
1.05 =
Vs =
Vs = 16.3 m/s