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fomenos
3 years ago
6

Please help with this!

Mathematics
2 answers:
GalinKa [24]3 years ago
8 0

Answer:

-88

Step-by-step explanation:

Because when you all ad it down you get -96 and then -8= -88

melisa1 [442]3 years ago
5 0

Answer:

-88

Step-by-step explanation:

24/3 = 8

24x-4 = -96

8+-96 = -88

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A formula is given that states 6x-k=wk. Solve this formula for k in terms of the other variables in the equation. ​
nadya68 [22]

Answer:

k = 6x/(w + 1)

Step-by-step explanation:

6x - k = wk

6x = wk + k

k(w+1) = 6x

k = 6x/(w + 1)

3 0
3 years ago
One solution of x^2-64=0 is 8. what is the other solution?
ivann1987 [24]
X² - 64 = 0
(x - 8)(x + 8) = 0

x = - 8, 8

Your other solution is - 8
4 0
3 years ago
Read 2 more answers
Solve the equation.<br><br>-4 (y - 2) = 12<br><br>y = ?​
inna [77]
First you distribute what’s outside the parentheses (the -4)

-4•4= -4y
-4•-2= 8

New equation: -4y+8=12

Now you solve like a normal equation
12-8 is 4

New equation: -4y=4

Now divide

Answer:-1
8 0
3 years ago
Find the distance traveled by a particle with position (x, y) as t varies in the given time interval. x = 5 sin2 t, y = 5 cos2 t
rodikova [14]
\begin{cases}x(t)=5\sin2t\\y(t)=5\cos2t\end{cases}\implies\begin{cases}\frac{\mathrm dx}{\mathrm dt}=10\cos2t\\\frac{\mathrm dy}{\mathrm dt}=-10\sin2t\end{cases}

The distance traveled by the particle is given by the definite integral

\displaystyle\int_C\mathrm dS=\int_0^{3\pi}\sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2}\,\mathrm dt

where C is the path of the particle. The distance is then

\displaystyle\int_0^{3\pi}\sqrt{100\cos^22t+100\sin^22t}\,\mathrm dt=10\int_0^{3\pi}\mathrm dt=30\pi
6 0
3 years ago
What is the relationship between the lines determined by the following two equations?
oksano4ka [1.4K]

Answer:

C. They are the same line.

Step-by-step explanation:

In order to compare the linear equations given, they need to be in the same form.  The best form in order to evaluate slope and y-intercept is slope-intercept form, y = mx + b.  Since the second equation is already in slope-intercept form, we need to use inverse operations to convert the first equation:

6x - 2y = 16 ----  6x - 2y - 6x = 16 - 6x ----  -2y = -6x + 16

-2y/-2 = -6x/-2 + 16/-2

y = 3x - 8

Since both equations are in the form y = 3x - 8, then they are both the same line.

4 0
3 years ago
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