<h2>Time Interval : 1 sec to 1.414 sec</h2>
Step-by-step explanation:
The height of the stuntperson jumping off a
is modelled as
. Here
is the time in seconds.
We have to record the person when he is between the heights
from the ground.
When
,
![15\text{ }=20\text{ }-\text{ }5t^{2}\\5t^{2}\text{ }=\text{ }5\\t^{2}\text{ }=\text{ }1\\t\text{ }=\text{ }1\text{ }sec](https://tex.z-dn.net/?f=15%5Ctext%7B%20%7D%3D20%5Ctext%7B%20%7D-%5Ctext%7B%20%7D5t%5E%7B2%7D%5C%5C5t%5E%7B2%7D%5Ctext%7B%20%7D%3D%5Ctext%7B%20%7D5%5C%5Ct%5E%7B2%7D%5Ctext%7B%20%7D%3D%5Ctext%7B%20%7D1%5C%5Ct%5Ctext%7B%20%7D%3D%5Ctext%7B%20%7D1%5Ctext%7B%20%7Dsec)
When
,
![10\text{ }=20\text{ }-\text{ }5t^{2}\\5t^{2}\text{ }=\text{ }10\\t^{2}\text{ }=\text{ }2\\t\text{ }=\text{ }\sqrt{2}\text{ }=\text{ }1.414\text{ }sec](https://tex.z-dn.net/?f=10%5Ctext%7B%20%7D%3D20%5Ctext%7B%20%7D-%5Ctext%7B%20%7D5t%5E%7B2%7D%5C%5C5t%5E%7B2%7D%5Ctext%7B%20%7D%3D%5Ctext%7B%20%7D10%5C%5Ct%5E%7B2%7D%5Ctext%7B%20%7D%3D%5Ctext%7B%20%7D2%5C%5Ct%5Ctext%7B%20%7D%3D%5Ctext%7B%20%7D%5Csqrt%7B2%7D%5Ctext%7B%20%7D%3D%5Ctext%7B%20%7D1.414%5Ctext%7B%20%7Dsec)
The stuntperson is at height
at
, and is at height
at
.
∴ The camera should film the person for the time interval
.
Answer:
b
Step-by-step explanation:
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You can replace the symbol x with the given value in the given equation and then calculate the value of y. Know that coefficients are in multiplication with the variables.
The value of y in the given equation when x = 0.3 is given by
Option C: 9.25
<h3>How to put values in a given expression of variables?</h3>
If you have got a variable's value in the given expression, you can replace that variable with the value that you got.
Suppose that the given expression is
and you know that x = 5, then you can put that value in place of x as:
![3x + 4|_{x=5} \: \: = \: \:3 \times (5) + 4 = 15 + 4 = 20](https://tex.z-dn.net/?f=3x%20%2B%204%7C_%7Bx%3D5%7D%20%20%20%20%20%5C%3A%20%5C%3A%20%3D%20%20%5C%3A%20%5C%3A3%20%5Ctimes%20%285%29%20%2B%204%20%3D%2015%20%2B%204%20%3D%2020)
It is because
means
and is written in short as ![3x](https://tex.z-dn.net/?f=3x)
<h3>Using the above conclusion for evaluating y</h3>
Putting the value x = 0.3 in the given equation, we get;
![5x + 2y = 20\\5 \times 0.3 + 2y = 20\\1.5 + 2y = 20\\\\\text{Subtracting 1.5 from both sides}\\\\1.5 - 1.5 + 2y = 20 - 1.5\\2y = 18.5\\\\\text{Dividing both sides by 2}\\\\\dfrac{2y}{2} = \dfrac{18.5}{2}\\\\\dfrac{2 \times y}{2} = y = 9.25](https://tex.z-dn.net/?f=5x%20%2B%202y%20%3D%2020%5C%5C5%20%5Ctimes%200.3%20%2B%202y%20%3D%2020%5C%5C1.5%20%2B%202y%20%3D%2020%5C%5C%5C%5C%5Ctext%7BSubtracting%201.5%20from%20both%20sides%7D%5C%5C%5C%5C1.5%20-%201.5%20%2B%202y%20%3D%2020%20-%201.5%5C%5C2y%20%3D%2018.5%5C%5C%5C%5C%5Ctext%7BDividing%20both%20sides%20by%202%7D%5C%5C%5C%5C%5Cdfrac%7B2y%7D%7B2%7D%20%3D%20%5Cdfrac%7B18.5%7D%7B2%7D%5C%5C%5C%5C%5Cdfrac%7B2%20%5Ctimes%20y%7D%7B2%7D%20%3D%20y%20%3D%209.25)
Thus,
The value of y in the given equation when x = 0.3 is given by
Option C: 9.25
Learn more about system of linear equations here:
brainly.com/question/13722693
Answer:
The corresponding pair are
Step-by-step explanation:
(0,_4) and (6,_4),(4,0) and (4,_10)
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