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3 years ago

Given a data set consisting of 33 unique whole number observations, its five-number summary is:

Mathematics

1 answer:

Lemur [1.5K]3 years ago

3 0

Answer:

given a data set of 33 unique whole number observation,its five number sumary is [16, 29, 40 ,54, 67]

Step-by-step explanation:

The p-th percentile in an ordered (from low to high) data set is a value such that p% of the data is less than that value. The quartiles of a data set are the 25th, 50th and 75th percentiles. (The 25th percentile is usually called the first quartile, the 50th percentile is usually called the median, and the 75th percentile is usually called the third quartile.)

The formula for finding the location (or position) of the (approximate) pth percentile in an ordered (from low to high) data set is

L p=(n+1).p/100

For example, in the data set [2,4,6,8,10,12,14,16,18]

the (approximate) 60th percentile is located at position

L 60=(9+1).60/100=6

that is, the sixth data point (the value 12) is at the (approximate) 60th percentile.(Actually, only 55.6% of the data is below a 12.)

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which equation shows the point-slope form of the line that passes through (3,2) and has a slope of 1/3

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Point slope form is
(y - y1) = m(x-x1)

m is a slope, m=1/3.
x1 = 3,
y1 = 2

(y-2) = (1/3)(x-3)

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3 years ago

Read 2 more answers

Find the equation of the line that passes through (-1,2) and is perpendicular to 2 y = 2 x − 1 . Leave your answer in the form y

Bogdan [553]

The equation in slope-intercept form of the line that passes through the point (-1, 2) and is perpendicular to the line equation, $2 y = 2 x - 1$ is: $y = -x + 1$

Recall:

Equation of a line in slope-intercept form is: $y = mx + c$ , where, slope = m, and y-intercept = c.

Point-slope form is: $y - b = m(x - a)$

The slope value of a line will be the negative reciprocal of the slope of the line it is perpendicular to. i.e. if the slope of a line is a, the slope of the line that it is perpendicular to will be -a.

Given:

The line passes through point (-1, 2)

Equation of line it is perpendicular to is: $2 y = 2 x - 1$

To write the equation of the line that passes through (-1, 2), we need to find the slope value.

First, rewrite $2 y = 2 x - 1$ and find its slope.

$\frac{2y}{2} = \frac{2x}{2} - \frac{1}{2} \\\\y = x - \frac{1}{2}$

The slope (m) of $2 y = 2 x - 1$ is therefore 1.

Thus, the slope (m) of the line that passes through (-1, 2) will be the negative reciprocal of 1 = -1.

Write the equation of the line by substituting (a, b) = (-1, 2) and m = -1 into $y - b = m(x - a)$ :

Thus:

$y - 2= -1(x - (-1))\\\\y - 2 = -1(x + 1)$

Rewrite this in the form of $y = m x + c$

Thus:

$y - 2 = -x - 1\\\\y = -x - 1 + 2\\\\y = -x + 1$

Therefore, the equation in slope-intercept form of the line that passes through the point (-1, 2) and is perpendicular to the line equation, $2 y = 2 x - 1$ is $y = -x + 1$

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Dovator [93]

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